1. Let P = (5, 3, 1), v = (1, 1, −1) and w = (1, 2, 2). Let us consider the straight lines R = {P + tv | t ∈ R}, and S = {P + tw | t ∈ R}.
Testo completo
Documenti correlati
To simplify the calculations, one can argue as follows: in this case the three vectors
Find all points of maximum and all points
We compute the cartesian equation of M.. See Test 3 of the
NOTE: In the solution of a given exercise you must (briefly) explain the line of your argument1. Solutions without adequate explanations will not
To satisfy the requirement that u is an eigenvalue of 1, we need that the first column of C is a vector parallel
Indeed we know that the maximal eigenvalue is the max- imum value taken by the quadratic form on the unit sphere (that is, the set of all
The answer is: the eigenvalues are all numbers of the form −n 2 , with n a (non-zero) natural number.. One arrives to this result by analyzing what is known for the solutions of
We follow the procedure indicated in the file ”Supplementary notes and exercises on linear transformations and matrices, II”, (see Week 14 of year 2012-’13),