Physical Cosmology 27/4/2017
Alessandro Melchiorri
alessandro.melchiorri@roma1.infn.it slides can be found here:
oberon.roma1.infn.it/alessandro/cosmo2016
T. Padmanabhan, structure formation in the universe Most of the discussion on BBN in current lectures
can be found here:
T>0.1 MeV Protons and
Neutrons are unbounded
T <0.1 MeV Protons and neutrons
are bounded to form light elements nuclei 4He, 3He, D, Li7
BBN at equilibrium
The photon/baryon appears here, to
the power of A-1 !
It is not enough to have BA>T
to have XA of order one !
We need to go to much lower temperatures ! This term is VERY
small !
BBN at equilibrium
We have XA of order one at a temperature:
this number is 3 for Helium 4
This number is about 22 This number is of order 10 Element
Binding
Energy TA at which XA is of order 1
Much much lower !!!!
BBN at equilibrium
Why we have this ?
We have many more CMB photons than baryons !
Photons are distributed as a blackbody at temperature T.
Even at temperatures much lower than the binding energy, we have in the tail of the distribution many photons at energies able to destroy that element !
BBN at equilibrium
This discussion however, while it gives a physical idea of what is going on is NOT correct because BBN happens out of equilibrium !
In particular we have assumed neutrons and protons in equilibrium at the same temperature T.
This is possible thanks to the weak interaction processes:
But neutrinos decouple at T=1 MeV !! these reactions are not working a T =0.1 MeV !
Helium abundance
A rough but uselful aestimate of the final Helium 4 abundance can be obtained also in this case.
Neutrons and protons are in equilibrium thanks to the following reactions:
At equilibrium we have that:
We have then that until equilibrium holds the neutron to proton numer density decreases as:
Helium abundance
The equilibrium will end when the rate of reactions is smaller than the Hubble parameter H(T).
Computing the quantity reaction rate times neutron lifetime this a function just of the temperature.
Reaction rate n to p (it flattens because of beta decay)
Reaction rate p to n
Twice Hubble rate. To be
compared to the sum of the two reaction rates.
T=0.8 MeV
Helium abundance
Assuming for the neutron lifetime a value of 915.4 s, we have a decoupling temperature of TD=0.8 MeV.
The neutron to proton ratio freezes at TD=0.7 MeV :
However the beta decay still works and we have a small decrease to n/p also for later times.
From the previous calculation we had that Helium could be produced only for T< 0.28 MeV. However Helium can be produced only if D is available thanks to the reactions:
and D starts to be present only for T < 0.1 MeV…
Helium abundance
Let us assume then that BBN start at T=0.1 MeV.
At this temperature the n/p ratio is reduced thanks to the beta decay (from 1 MeV to 0.1 MeV) by a factor 0.8, to:
BBN
Assuming that at end of BBN all neutrons go to form Helium 4 (this is quite correct) we have for the
Helium mass fraction:
in agreement with the observations of primordial Helium in the Universe ! Stellar nucleosynthesis is unable to
produce such large abundance of Helium !!
Nice and very pedagogical review
BBN: accurate calculations
In order to properly compute the several abundances we need to integrate a system of Boltzmann equations.
There are several numerical codes available to do this.
In Figure we see that Helium abundance starts to be there just after D reaches enough mass fraction.
BBN: numerical calculations
BBN starts only after D is formed.
Mostly of the
neutrons goes to Helium.
Standard BBN
If we assume 3 neutrinos then BBN has just one
free parameter,
the baryon to photon ratio:
i.e. the baryon (atoms) energy density.
Predictions for the elements are in the figure in function of the baryon density.
The width of the lines are due to uncertainties in the rates.
Why we have mostly He4 ?
Helium “peak”.
If we plot nucleon binding energy versus A
we see that Helium has a
“peak”.
i.e. nuclei with larger A (6-7) are less stable.
The nuclei density is small, we don’t have any triple alpha:
Universe is expanding. BBN ends after few minutes.
Standard BBN
As we will see, observations can restrict the range in the baryon density to:
In this range we have the following approximated formulas:
What enters in the computations are several reaction rates.
Some of them are really well measured others are not.
In the estimate of D the largest error
comes from this reaction (6%)
BBN: systematics
BBN: systematics
Taken from Nollett and Holder
http://arxiv.org/pdf 1112.2683.pdf.
Few datapoint and in tension with theoretical expectations.
The LUNA400 experiment under Gran Sasso could measure the reaction rate with the better
accuracy.
BBN: Systematics
The largest systematic we have for the final Helium abundance comes from the measurement of the neutron lifetime !
Particle data group
http://pdg.lbl.gov/2014/listings/rpp2014-list-n.pdf
quotes 1.1 s error, but it comes from measurements that are scattered….
BBN:neutron lifetime
Measuring the neutron lifetime is fundamental in measuring the Fermi constant:
that enters in the weak interactions rate:
that fixes the neutron freeze-out that happens when:
BBN neutron lifetime
Lower neutron lifetime
Higher reaction rate
Freeze out happens later (smaller T) Lower density of neutrons at BBN start
Lower final Helium abundance predicted
Non-standard BBN
There is the possibility of having extra relativistic particles at BBN.
This can be parametrized by
increasing the effective neutrino number.
This increases the radiation content:
We then have larger H at BBN.
The freeze-out happens earlier (larger T).
We have more neutrons at BBN, more helium !
Non-standard BBN
We also have approximate formulas in this case if:
If we define:
We have:
http://parthenope.na.infn.it
http://superiso.in2p3.fr/relic/alterbbn/
Observations of primordial abundance of light elements
BBN theory predicts with high precision the amount of primordial Helium, Deuterium and Lithium.
These predictions depend on the baryon density and on the neutrino effective number.
If we could have a precise measurement of primordial abundances we could infer constraints on these
parameters of the theory.
Stellar nucleosynthesis can produce/destroy primordial abundances, how we can derive the primordial values ?
Observations of primordial Helium
Observations are made by looking at Helium lines in extragalactic HII regions (ionized hydrogen).
Stellar activity is tracked by metallicity, (O/H) for example.
The value of Yp (primordial Helium 4) can be recovered by extrapolating at “low metallicities”.
In practice one expects that going to O/H=0 the
Yp abundance should flattens to the primordial value.
Expectations vs Reality
We don’t see much (any) flattening going
to zero O/H (zero metallicity)
From this dataset (2007) we can derive the constraint:
Systematics in the recovery of Yp
Constraints during the years have improved in
precision but not in accuracy.
There is a large scatter in the measurements.
Systematics are important.
Value obtained from SBBN assuming baryon density
consistent with cosmic microwave background anisotropies.
Recent developments
Constraints on Yp have been improved by observations of the He I λ10830 line that strongly traces the electron
density of the HI region and helps in breaking degeneracies with temperature of the HI region.
Strongest dependence on ne compared
to other lines
Lower dependence on Temperature
Analysis by Izotov, Thuan and Guzeva, 2014
Following this method, observations made by Izotov and Thuan found an higher Helium abundance.
http://arxiv.org/pdf/1408.6953v1.pdf
Analysis by Izotov, Thuan, Guzeva 2014
Assuming BBN e combining with observations
of primordial D (see next slides) IT found a best
fit value for a larger than 3.046
neutrino number !
Aver et al, 2015
http://arxiv.org/pdf/1503.08146v1.pdf extrapolated value
at zero metallicity Flattening is still not really clear…
However, a more recent analysis by Aver at al., has found a lower value, consistent with Neff=3.046
Primordial Deuterium
Deuterium is destroyed by stellar nucleosynthesis.
Best measurements are again, in low metallicity regions.
The best way to probe it is in damped lyman alpha systems.
Primordial Deuterium
At rest, the Lyman-alpha line (transition from level n=1 to n=2 in neutral H)
is at wavelength of 1216 Å.
Along the line of sight we
have many clouds, each of them absorbing the Lyman-alpha at wavelenght (1+z)1216 Å
Quasars light is absorbed by neutral H clouds between us and the quasar.
Primordial Deuterium
At rest, the Lyman-alpha line (transition from level n=1 to n=2 in neutral H)
is at wavelength of 1216 Å.
Along the line of sight we
have many clouds, each of them absorbing the Lyman-alpha at wavelenght (1+z)1216 Å
Primordial Deuterium
Cloud is at z=3.572.
Lyman-alpha absorption is at (1+z)Lya = 5557 Å
It falls in the visible (4000-7000)Å !
We can measure it from earth !
1216Å is on the UV.
It would be absorbed by the atmosphere.
Primordial Deuterium
Cloud is at z=3.572.
Lyman-alpha absorption is at (1+z)Lya = 5557 Å
It falls in the visible (4000-7000)Å !
We can measure it from earth !
1216Å is on the UV.
It would be absorbed by the atmosphere.
Primordial Deuterium
We see here a “damped"
lyman-alpha system large column density N > 2*10^20 /cmˆ2
In these systems is "easier" to isolate the D line from H lines
from other systems and clouds.
In reality this was possible just in about 10 cases.
Primordial Deuterium
We see here a “damped"
lyman-alpha system large column density N > 2*10^20 /cmˆ2
In these systems is "easier" to isolate the D line from H lines
from other systems and clouds.
In reality this was possible just in about 10 cases.
ISM In the Interstellar Medium we measure low values.
Chengalur, Braun e Burton(1997) looking in a
direction opposite to the galactic center :
(3.9 ±1.0)⋅10−5
H = D
Libowich (2000),
Looking towards the galactic center:
(1.7 ± 0.3)⋅10−6
H =
>> D
ISM In the Interstellar Medium we measure low values.
Chengalur, Braun e Burton(1997) looking in a
direction opposite to the galactic center :
Solar System
(3.9 ±1.0)⋅10−5
H = D
Libowich (2000),
Looking towards the galactic center:
(1.7 ± 0.3)⋅10−6
H =
>> D
Jupiter atmosphere (Mahaffy et al. 1998) :
(2.6 ± 0.7)⋅10−5
H = D
Solar wind (Gloecker, 1999) :
(1.94 ± 0.36)⋅10−5
H = D
Primordial Deuterium
Measurements @2007 based on Lyman-alpha.
We see a large scatter.
No clear plateau at small metallicities but values
are higher respect to
“local" measurements.
Measurements in our solar system and
interstella medium.
We can consider them just as lower limit since we had stellar activity.
Primordial Deuterium
The best measurement comes from DLA of Pettini & Cooke
http://arxiv.org/pdf/1205.3785.pdf that gives:
Combined with other measurements we have:
Primordial Deuterium
Once we have a D
measurement we can trace a line on this
plane and considering the intersection with the BBN predictions we
can bound eta and the baryon density.
We get:
Consistency D and He4
When comparing with Helium data
we found consistency with the measurements of Aver et al, 2015
but not with
Izotov et al, 2014 but this assumes standard BBN !
Izotov et al, 2014 Aver et et al, 2015
Consistency D and He4
You can increase
Helium by increasing Neff ! You keep same Yp by
increasing eta and lowering Neff
Deuterium depends also by Neff
You have same D increasing eta and increasing Neff
Consistency D and He4
Using both Helium and D measurements we can constrain both Neff and the baryon density.
Using Cooke and Pettini and Izotov et al., we get:
Constraint from D Pettini and Cooke
Constraint from He4 Izotov 2014
Neff>3.046 ? Systematics
may be present…
Lithium 7
Primordial Lithium is measured on very old
stars with low metallicity in our galaxy or globular clusters.
When we go to lower metallicities we see a plateau….
… but the value is in
complete disagreement with the expectations from standard BBN.
Observed:
Spite Plateau
Again, we plot the Lithium abundance in
function of the metallicity.
At lower metallicities we see a plateau: «Spite
Plateau»
That should indicate The primordial
abundance.
Lithium 7
The values of the baryon
density inferred from D and Li7 are very different if we
assume SBBN !!
The problem of Lithium 7
- In old stars we see a plateau as expected but the Lithium abundance is far lower than expected !
- We don’t see old stars with higher Lithium abundance ! (Lithium desert).
- We see higher Lithium abundance in the small Magellan cloud. But this system has an high metallicity. If we have
depletion of Lithium 7 by stars, why we have more Lithium in stars with higher metallicity ?
- We may have new physics in BBN, but this would alter D abundance. It is difficult to avoid this.
Big Bang Nucleosynthesis
The consequences of BBN are (from D measurements):
Assuming h=0.67 we get:
Since SN-Ia, assuming a flat universe, gives:
About 80% of the matter in the universe should be Non Baryonic !!!