PATRIZIA BERTI, LUCA PRATELLI, AND PIETRO RIGO
Testo completo
E γn
Since γ n ∈ F (µ 0 , µ n ), then W (µ n , µ 0 ) ≤ E γn
E γn
Conversely, suppose W (µ n , µ 0 ) → 0, and take a sequence γ n ∈ F (µ 0 , µ n ), n ≥ 1, such that E γn
As to (a), the remark at the beginning of this proof yields E P 1 ∧ d(X 0 , X n ) = E γn
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