1
AY 2017-2018
Economics of Money and Banking
Simulation second mid term test (Monday 18 June) Solutions
Prof. Nicola Dimitri
Available time: 90 Minutes
1. (11 points)
In the General Equilibrium with banks model discussed in class suppose consumers have the following utility function
π(π1, π2) = π1+ ππππ2 and that the firms production function is
π(πΌ) = πππ (1 + πΌ)
where π1, π2, πΌ β₯ 0. Find the General Equilibrium values of quantities and prices of this economy
Discussion
Because in equilibrium π = ππ΅ = ππΏ = ππ· it is easier to start considering the firm profit as function of πΌ = πΏπ+ π΅π rather than πΏπ, π΅π separately, since loans and bonds are perfect substitutes
Ξ π(πΌ) = π (πππ(1 + πΌ)) β (1 + π)πΌ (1) Maximising (1) with respect to πΌ gives as FOC
π
(1 + πΌ)β (1 + π) = 0 (2) Because the second derivative of (1) is β π
(1+πΌ)2 < 0 solution to (2) provides a maximum for (1). Solving (2) gives the optimal investment level πΌβas
πΌβ = { π
1 + πβ 1 ππ π > (1 + π) 0 ππ‘βπππ€ππ π Assuming π > 1 + π it follows then (1) becomes
Ξ π(πΌβ) = π log ( π
1 + π) β π + (1 + π) > 0 (3)
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2
Likewise, defining π = π΅β+ π·β as the household savings, and since the bank profit Ξ π = 0, maximisation of the utility π(π1, π2) = π1+ ππππ2 with respect to savings, subject to the constraints π1 = π€1β π and ππ2 = Ξ π+ (1 + π)π , leads to the following first order conditions
β1 + (1 + π)
Ξ π+ (1 + π)π = 0 (4)
Because second order conditions for a maximum are satisfied, solution π β to (4) provides the optimal level of savings and is given by
π β = {1 β Ξ π
(1 + π) ππ Ξ π < (1 + π) 0 ππ‘βπππ€ππ π
The savings=investments equilibrium condition
π β = 1 β Ξ π
(1 + π)= π
1 + πβ 1 = πΌβ
will determine how π and π should relate. Finally, any combination of the remaining quantities Bπ, Bπ, Bβ, Lπ, Lπ, Dπ, Dπ, such that the rest of the equilibrium conditions are satisfied represents a general equilibrium of the economy.
2 (11 points) Consider the Diamond-Dybvig model for banks as liquidity providers, in case of negative shocks, discussed in class.
Suppose π’(π) = ππ with 0 < π < 1. Find the autharky solution, the market solution and the Pareto Optimal solution for the investment level πΌ and consumption levels π1, π2. Is the market solution Pareto Efficient?
Discussion
The autarky solution requires maximisation of the expected utility ππ’(π1) + (1 β π)π’(π2)
with respect to πΌ subject to the constraints π1 = 1 β πΌ + ππΌ and π2 = 1 β πΌ + π πΌ. Assuming that FOC identify a maximum then the optimal level of investment πΌπ is given by
πΌπ = 1 β ππ
(1 β π) β ππ(π β 1) (1) where ππ = [ π(1βπ)
(1βπ)(π β1)]1βπ1 . When replaced in the constraints (1) typically provides π1 and π2 which differ from the market condition, π1 = 1 and π2 = π . The Pareto Optimal allocation is given by
3
πΌππ = 1 β πππ
(1 β π) β πππ(π β 1) (2)
where πππ = (1
π )
1
1βπ, leading to consumption levels in the two periods that are typically different from the market solution.