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Contour Locus: examples

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0.0. 5.4 1

Contour Locus: examples

Let us refer to the following differential equation which describes the dynamics of a “mass, spring, damper” system:

M ¨x(t) + b ˙x(t) + K x(t) = F (s) The corresponding transfer function is:

G(s) = X(s)

F (s) = 1

M s2 + b s + K

The dynamic behavior of the given system depends on the position of the pole of function G(s) and, therefore, on the value of parameters M , b and K.

Contour locus of G(s) as a function of parameter b > 0. The poles of system G(s) are the poles of the following equation:

M s2 + b s + K = 0 which can be rewritten as follows:

1 + b s

M s2 + K = 0 The corresponding root locus

when b > 0 (see the figure) shows that the minimum settling time is at the branching point σa:

σa = −r K M

The corresponding “optimal va- lue” of parameter b is:

b = − 1 G(s)

s=σa

= 2√

K M

Re

Im M K

M K - M

K -

Re

Im M K

M K - M

K -

(2)

5.4. CONTOUR LOCUS 5.4 2

Contour locus of G(s) as a function of parameter M > 0. The equation which provides the poles of function G(s) can be rewritten as follows:

1 + M s2

b s + K = 0 The corresponding root locus

when M > 0 (see the figure) sho- ws that the minimum settling time is obtained at the branching point:

σd = −2K b

The corresponding “optimal va- lue” of parameter M is:

M = − 1 G(s)

s=σd

= b2 4K

Re

Im

b 2K -

b K -

Re

Im

b 2K -

b K -

Electric system R, L, C.

The transfer function G(s) of the electrical system (see the figure) can be obtained as follows:

IL

C Vi

Iu=0 L R

Vu IL

C Vi

Iu=0 L R

Vu

G(s) = Vu(s) Vi(s) =

1 C s

L s + R + C s1 =

1 C

L s2 + R s + C1

The parametric analysis of this electric system can be directly obtained from the parametric analysis of the previous mechanical system using the following analogies:

L ↔ M, R ↔ b, C ↔ 1

K

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