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Existence of blowing-up solutions for a nonlinear elliptic equation with Hardy potential and critical

growth

Veronica FELLI and Angela PISTOIA

January 8, 2004

Abstract We prove the existence of a positive solution to

−∆u − λ

|x| 2 u = k(x)u 2

−1 , u ∈ D 1,2 (R N ),

which blows-up at a suitable critical point of k as the positive parameter λ goes to zero.

Keywords: Hardy potential, Sobolev critical exponent, perturbation methods.

AMS subject classification: 35J70, 35J20, 35B33.

0 Introduction

Let us consider the following nonlinear elliptic equation

−∆u − |x| λ

2

u = k(x)u 2

−1 in R N , u ∈ D 1,2 (R N ), u > 0 in R N ,

(0.1)

where N ≥ 3, 2 = N −2 2N and the space D 1,2 (R N ) is the closure of C 0 (R N ) with respect to the norm

kuk :=

 Z

R

N

|∇u| 2 dx

 1/2

. (0.2)

The first author is supported by M.U.R.S.T. project “Variational Methods and Nonlinear Differential Equa- tions”. The second author is supported by M.U.R.S.T. project “Metodi variazionali e topologici nello studio di fenomeni non lineari”.

Dipartimento di Matematica e Applicazioni, Universit` a di Milano Bicocca, Via Bicocca degli Arcimboldi 8, 20126 Milano, Italy. E-mail: [email protected].

Dipartimento di Metodi e Modelli Matematici, Universit` a di Roma “La Sapienza”, 00100 Roma, Italy. E-mail:

[email protected].

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We point out that one of the main features of problem (0.1) is a lack of compactness due to the critical growth of the nonlinearity. Non-existence results for (0.1) can be obtained using the Pohozaev type identity proved in [13] ; more precisely it turns that any positive solution to (0.1) in the space D 1,2 (R N ) satisfies the following identity

Z

R

N

h∇k(x), xiu 2

dx = 0

provided k is continuously differentiable. This implies that ther are no such solution if h∇k(x), xi does not change sign and k is not constant .

When λ = 0 and k ≡ 1, it is well known (see [5], [7] and [14]) that all the solutions to (0.1) are given by

U δ,ξ (x) := α N

δ

N −22

2 + |x − ξ| 2 )

N −22

, x ∈ R N , ξ ∈ R N , δ > 0, (0.3) where α N = [N (N − 2)] (N −2)/4 .

The case λ 6= 0 and k ≡ 1 has been studied by Terracini in [15], where a solution to (0.1) is found explicitly provided 0 < λ < (N − 2) 2 /4 , namely:

V λ (x) := c λ (N )

[|x| 1−a (1 + |x| 2a )]

N −22

,

where a := p1 − 4λ/(N − 2) 2 and c λ (N ) is a suitable positive constant. This solution is also unique, up to a conformal transformation of the form V λ ε (x) := ε (2−N )/2 V λ (x/ε) for some ε > 0.

In [13] Smets considers the case N = 4 and proves that if k satisfies the “global” condition k(0) = lim |x|→+∞ k(x), then for any λ ∈ (0, 1) problem (0.1) has at least one solution.

In [8] Schneider and the first author consider the case N ≥ 3 (even for a more general class of differential operators related to Caffarelli-Kohn-Nirenberg inequalities) and assume that k is close to a constant, i.e. k(x) = 1 + εh(x), where h satisfies a suitable “global” condition and ε is a small real perturbation parameter. By using the perturbative method by Ambrosetti and Badiale [3], they find a solution to (0.1) which is close to a radial solution to the unperturbed problem, provided 0 < λ < (N − 2) 2 /4 and ε small enough.

In [1] Abdellaoui, Peral, and the first author prove the existence of solutions to problem (0.1) blowing-up at global maximum points of k as the parameter λ goes to zero, under some suitable assumption about the local behaviour of k close to such maximum points.

Let us also mention that some related singular equations with Hardy type potential were also studied in [2, 9, 10, 12].

In this paper we are interested in finding solutions to problem (0.1) blowing-up at a suitable critical point (not necessarily a maximum point) ξ 0 of the function k, as the parameter λ goes to zero (see Definition 0.1).

Before stating our main result it is useful to introduce some notation. Let ξ 0 ∈ R N be such that k(ξ 0 ) > 0 and set (see (0.3))

W δ,ξ (x) := k(ξ 0 )  −

2∗−21

U δ,ξ (x). (0.4)

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Then for δ > 0 and ξ ∈ R N the functions W δ,ξ ∈ D 1,2 (R N ) solve the limit equation

−∆W = k(ξ 0 )W 2

−1 in R N ,

W > 0 in R N .

We can introduce the following definition.

Definition 0.1 Let u λ be a solution to problem (0.1). We say that u λ blows-up at ξ 0 as λ goes to zero if there exist δ λ > 0 and ξ λ ∈ R N such that lim λ→0 δ λ = 0, lim λ→0 ξ λ = ξ 0 and u λ − W δ

λ

λ

→ 0 in D 1,2 (R N ).

Let us assume k ∈ L (R N ) ∩ C 0 (R N ). We state below our main assumption on k and ξ 0 .

(∗)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Let ξ 0 ∈ R N \ {0} be a critical point of k with k(ξ 0 ) > 0 such that for some r > 0

k(x + ξ 0 ) = k(ξ 0 ) + Q ξ

0

(x) + R ξ

0

(x) ∀ x ∈ B(0, r) := {x ∈ R N : |x| < r}, (0.5) where Q ξ

0

: R N −→ R is a continuous function such that for some θ ∈ (2, N)

Q ξ

0

(tx) = t θ Q ξ

0

(x) ∀ x ∈ R N , t > 0, (0.6) and R ξ

0

: B(0, r) −→ R is a continuous function such that for some  ∈ (0, N − θ)

|R ξ

0

(x)| ≤ c|x| θ+ ∀ x ∈ B(0, r). (0.7) Condition (∗) should be compared to the so-called flatness assumptions in the problems of prescribing scalar curvature arising in differential geometry (see for example [4] and [11]). Our main result is the following.

Theorem 0.2 Let us assume that (∗) holds with Q ξ

0

(x) = P N

i=1 a i x θ i , x ∈ R N , where θ is an even integer. Assume either

θ ∈ (2, N ) and a i < 0 for any i = 1, . . . , N (0.8) or

θ ∈

 max



2, N − 2 4

 , N

 ,

N

X

i=1

a i < 0, and a i 6= 0 for any i = 1, . . . , N. (0.9)

Then for λ small enough there exists a solution to problem (0.1) which blows-up at ξ 0 as λ goes to zero (see Definition 0.1).

We quote the fact that we prove the existence of solutions to (0.1) blowing-up at a point ξ 0

which is a critical point of k with k(ξ 0 ) > 0, by only requiring a suitable condition on k in a

neighborhood of ξ 0 .

(4)

The proof of Theorem 0.2 is based on a Ljapunov-Schmidt reduction method (see, for ex- ample, [6]). We would like to point out that our method could also allow to construct solutions blowing-up at m different critical points ξ 1 , . . . , ξ m of the function k, provided assumptions (0.5–0.7) hold and either (0.8) or (0.9) are satisfied at each point ξ i .

The paper is organized as follows. In Section 1 we reduce the problem to a finite dimensional one and in Section 2 we prove Theorem 0.2, by studying the reduced problem. In Appendix A and Appendix B we prove some technical results used in Section 1 and Section 2, respectively.

In Appendix C some useful estimates are given.

1 The finite dimensional reduction

Equation (0.1) is related to the Hardy inequality. For the reader’s convenience we recall it below referring for instance to [9] for a proof.

Lemma 1.1 (Hardy inequality) If u ∈ D 1,2 (R N ), then |x| u ∈ L 2 (R N ) and C N

Z

R

N

u 2

|x| 2 dx ≤ Z

R

N

|∇u| 2 dx, (1.1)

where C N = N −2 2  2

is optimal and not attained.

For any λ ∈ (0, C N ) let us introduce the Hilbert space D λ := D 1,2 (R N ) equipped with the inner product

(u, v) λ :=

Z

R

N



∇u∇v − λ

|x| 2 uv

 dx, which induces the norm

kuk λ :=

 Z

R

N



|∇u| 2 − λ

|x| 2 u 2

 dx

 1/2

. By the Hardy inequality (1.1) we get that

 1 − λ

C N

 1/2

kuk ≤ kuk λ , (1.2)

hence k · k λ and k · k are equivalent norms. By (1.2) we deduce that kuk L

2∗

(R

N

) ≤

 S

 1 − λ

C N

 −1/2

kuk λ , (1.3)

where S is the best Sobolev costant of the embedding D 1,2 (R N ) ,→ L 2

(R N ), i.e. the best constant in the Sobolev inequality

Skuk 2 L

2∗

(R

N

) ≤ kuk 2 D

1,2

(R

N

) . (1.4)

Let i λ : D λ ,→ L 2

(R N ) denote the embedding.

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Definition 1.2 Let i λ : L

N +22N

(R N ) → D λ be the adjoint of i λ , namely (i λ u, v) λ =

Z

R

N

uv dx ∀ v ∈ D λ , or equivalently w := i λ u is the unique solution to

−∆w − λ

|x| 2 w = u in R N , w ∈ D 1,2 (R N ).

From H¨ older inequality and (1.3) we obtain easily the following lemma.

Lemma 1.3 i λ : L

N +22N

(R N ) → D λ is a continuous operator and

ki λ (u)k λ

 S

 1 − λ

C N

 −1/2

kuk

L

2N

N +2

for any u ∈ L

N +22N

(R N ).

Problem (0.1) is equivalent to the following one

u = i λ k(x)f (u)), u ∈ D λ , (1.5)

where f (s) := (s + ) 2

−1 . We will look for solutions to (1.5) of the following form u(x) = W δ,ξ (x) + φ(x)

where the rest term φ is a lower order term belonging to a suitable space. Set for j = 1, . . . , N ψ δ,ξ j (x) := ∂W δ,ξ

∂ξ j (x) = α N (N − 2)k(ξ 0 )  −

1

2∗−2

δ

N −22

x j − ξ j2 + |x − ξ| 2 )

N2

(1.6) and

ψ δ,ξ 0 (x) := ∂W δ,ξ

∂δ (x) = α N (N − 2)

2 k(ξ 0 )  −

2∗−21

δ

N −42

|x − ξ| 2 − δ 2

2 + |x − ξ| 2 )

N2

. (1.7) The N + 1 functions ψ δ,ξ j solve the linearized problem

−∆ψ = (2 − 1)k(ξ 0 )W δ,ξ 2

−2 ψ in R N , ψ ∈ D 1,2 (R N ).

(1.8)

Remark 1.4 It is known that the space of the solutions to problem (1.8) in D 1,2 (R N ) is the linear space spanned by the hψ j δ,ξ i j=0,1,...,N (see [4, Lemma 3.1]).

Let

K δ,ξ λ = n

φ ∈ D λ

ψ δ,ξ j , φ 

λ = 0 ∀ j = 0, 1, . . . , N o

(1.9)

and let Π λ δ,ξ : D λ −→ K δ,ξ λ be the orthogonal projection.

(6)

Proposition 1.5 There exist Z ⊂⊂ R N such that ξ 0 ∈ Z, λ 0 > 0 and δ 0 > 0 such that for any λ ∈ (0, λ 0 ), δ ∈ (0, δ 0 ) and ξ ∈ Z there exists a unique φ λ δ,ξ ∈ K δ,ξ λ such that

Π λ δ,ξ n

W δ,ξ + φ λ δ,ξ − i λ h k(x)f



W δ,ξ + φ λ δ,ξ

io

= 0. (1.10)

Moreover

λ δ,ξ k λ =

 

 

 

 

O |ξ − ξ 0 | θ + δ θ + λδ 2 

if N ≥ 5, O |ξ − ξ 0 | θ + δ θ + λδ 2 log δ 

if N = 4, O |ξ − ξ 0 | θ + δ θ + λδ 

if N = 3.

(1.11)

Proof. See Appendix B.

Let us introduce the functional J λ : D 1,2 (R N ) −→ R defined by J λ (u) = 1

2 Z

R

N

|∇u| 2 dx − λ 2

Z

R

N

u 2

|x| 2 dx − 1 2

Z

R

N

k(x)(u + ) 2

dx.

It is well known that u is a critical point of J λ if and only if u is a solution to problem (0.1).

The following result allows to reduce the problem of existence of solutions to (0.1) to the existence of critical points of a real-valued function of N + 1 variables.

Proposition 1.6 There exist Z ⊂⊂ R N such that ξ 0 ∈ Z, λ 0 > 0 and δ 0 > 0 such that for any λ ∈ (0, λ 0 ), δ ∈ (0, δ 0 ) and ξ ∈ Z the function W δ,ξ + φ λ δ,ξ is a solution to problem (0.1) if and only if (δ, ξ) is a critical point of the function

J e λ (δ, ξ) := J λ 

W δ,ξ + φ λ δ,ξ 

. (1.12)

Proof. See Appendix B.

2 The reduced problem

Let us introduce the function I λ : R N × R + −→ R defined by (see (1.12))

I λ (ζ, d) := e J λ δ(d, λ), ξ(ζ, d, λ), (2.1) where

δ(d, λ) :=

 

 

 

 

θ−11

if N = 3, dλ

θ−21

| log λ|

θ−21

if N = 4, dλ

θ−21

if N ≥ 5,

(2.2)

and

ξ(ζ, d, λ) := ξ 0 + δ(d, λ)ζ. (2.3)

(7)

Proposition 2.1 Let K ⊂ R N be a compact set and b > a > 0 be fixed. If (∗) is satisfied and θ ∈ (2, N ), there holds

I λ (d, ζ) =

 

 

 

 

a 30 ) − Γ ξ

0

(d, ζ)λ

θ−1θ

+ o λ

θ−1θ

, if N = 3, a 4 (ξ 0 ) − Γ ξ

0

(d, ζ)λ

θ−2θ

| log λ|

θ−2θ

+ o λ

θ−2θ

| log λ|

θ−2θ

, if N = 4, a N0 ) − Γ ξ

0

(d, ζ)λ

θ−2θ

+ o λ

θ−2θ

, if N ≥ 5,

(2.4)

C 0 -uniformly with respect to ζ in K and to d in [a, b]. If, in addition, θ ∈ max 2, N −2 4 , N  , estimate (2.4) holds C 1 -uniformly with respect to ζ in K and to d in [a, b].

The function Γ ξ

0

: R + × R N → R in (2.4) is defined by

Γ ξ

0

(d, ζ) = b N (ξ 0 )d θ Z

R

N

Q ξ

0

(y + ζ) (1 + |y| 2 ) N dy +

c 30 )d if N = 3, c N0 )d 2 if N ≥ 4,

(2.5)

and

a N0 ) : =  1 2 − 1

2



α 2 N

[k(ξ 0 )]

2∗−22

Z

R

N

dx

(1 + |x| 2 ) N , (2.6)

b N (ξ 0 ) : = 1

2 α 2 N

[k(ξ 0 )]

2∗−22∗

, (2.7)

c N0 ) : =

 

 

 

 

 

 

 

  1

2 α 2 3 [k(ξ 0 )] −1/2 Z

R

N

1

|x − ξ 0 | 2 1

|x| 2 dx, if N = 3, α 2 4 k(ξ 0 ) −1

2(θ − 2)|ξ 0 | 2 , if N = 4,

1

2 α 2 N [k(ξ 0 )]

2∗−22

1

0 | 2 Z

R

N

dx

(1 + |x| 2 ) N −2 , if N ≥ 5.

(2.8)

Proof. See Appendix C.

Definition 2.2 Let g : D → R be a C 1 -function, where D ⊂ R m is an open set, m ∈ IN. Let x 0 be a critical point of g.

(i) We say that x 0 is a C 0 -stable critical point of g if for any sequence g n : D → R with g n → g C 0 -uniformly in D there exists x n ∈ D such that ∇g n (x n ) = 0 and x n → x 0 . (ii) We say that x 0 is a C 1 -stable critical point of g if for any sequence g n : D → R with

g n → g C 1 -uniformly in D there exists x n ∈ D such that ∇g n (x n ) = 0 and x n → x 0 .

We point out that any strict local maximum point or strict local minimum point of g is a C 0 -

stable critical point of g. Moreover any non degenerate critical point of g is a C 1 -stable critical

point of g. Let us remark that a non degenerate critical point is not necessarily a C 0 -stable

critical point as the following example shows.

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Example 2.3 Let g : R 2 → R, g(x, y) = xy. (0, 0) is a C 1 -stable critical point, but it is not a C 0 -stable critical point.

Proof. It is easy to verify that (0, 0) is a non degenerate critical point. Let us consider the sequence of functions g n (x, y) := xy + 1 n sin(nx), n ∈ IN. The sequence {g n } n∈IN converges to g uniformly in R 2 . If (x n , y n ) is a critical point of g n , then a direct computation shows that necessarily x n = 0 and y n = −1 for any n ∈ IN. Therefore there can not exist any sequence of critical points of g n converging to (0, 0). Hence (0, 0) is not a C 0 -stable critical point.

Theorem 2.4 Assume either θ ∈ (2, N ) and (d 0 , ζ 0 ) is a C 0 -stable critical point of Γ ξ

0

(d, ζ) or θ ∈ max 2, N −2 4 , N  and (d 0 , ζ 0 ) is a C 1 -stable critical point of Γ ξ

0

(d, ζ). Then for λ small enough there exists a critical point (δ λ , ξ λ ) of the function e J defined in (1.12).

Proof. By Proposition 2.1 and Definition 2.2 it follows that there exists a critical point (d λ , ζ λ ) of I λ such that lim λ→0 d λ = d 0 and lim λ→0 ζ λ = ζ 0 . If δ λ is defined as in (2.2) and ξ λ is defined as in (2.3), it is easy to check that (δ λ , ξ λ ) is a critical point of e J .

Proposition 2.5 Assume Q ξ

0

(x) = P N

i=1 a i x θ i , x ∈ R N , where θ ∈ (2, N ) is an even integer. If a i < 0 for any i = 1, . . . , N, there exists a strict maximum point of the function Γ ξ

0

, which is a C 0 -stable critical point according to Definition 2.2.

Proof. Since necessarily N ≥ 5, we can write function Γ ξ

0

as Γ(d, ζ) = b N d θ f (ζ)+c N d 2 , where

f (ζ) :=

Z

R

N

Q ξ

0

(y + ζ) (1 + |y| 2 ) N dy =

N

X

i=1

a i Z

R

N

(y i + ζ i ) θ

(1 + |y| 2 ) N dy. (2.9) We claim that

f (ζ) < f (0) < 0 ∀ ζ ∈ R N \ {0}. (2.10) Indeed

Z

R

N

(y i + ζ i ) θ (1 + |y| 2 ) N dy =

Z

R

N

y i θ

(1 + |y| 2 ) N dy +

θ

X

k=2 keven

θ k

 Z

R

N

y θ−k i ζ i k

(1 + |y| 2 ) N dy ≥ Z

R

N

y i θ (1 + |y| 2 ) N dy with equality only for ζ i = 0 and claim (2.10) follows, since a i < 0 for any i. Let us set d 0 :=

h −2c

N

b

N

θf (0)

i

θ−21

. Note that the definition of d 0 makes sense because of (2.10). We claim that (d 0 , 0) is a strict maximum point of Γ ξ

0

. (2.11) Indeed by (2.10) we deduce that for any ζ it holds

Γ(d, ζ) ≤ Γ(d, 0) ≤ Γ(d 0 , 0) = max

d∈R

+

Γ(d, 0).

If (d, ζ) 6= (d 0 , 0) then either d 6= d 0 and hence Γ(d, 0) < Γ(d 0 , 0) or ζ 6= 0 and hence from (2.10)

Γ(d, ζ) < Γ(d, 0). Therefore for any (d, ζ) 6= (d 0 , 0) we have Γ(d, ζ) < Γ(d 0 , 0).

(9)

Proposition 2.6 Assume Q ξ

0

(x) = P N

i=1 a i x θ i , x ∈ R N , where θ ∈ (2, N ) is an even integer. If P N

i=1 a i < 0 and a i 6= 0 for any i = 1, . . . , N, there exists a non degenerate critical point of the function Γ ξ

0

, which is a C 1 -stable critical point according to Definition 2.2.

Proof. As above, since N ≥ 5, we can write function Γ ξ

0

as Γ(d, ζ) = b N d θ f (ζ) + c N d 2 , where f is defined in (2.9). We point out that

f (0) = d N N

X

i=1

a i < 0,

where d N := R

R

N

y 1 θ (1 + |y| 2 ) −N dy. Therefore it makes sense to set d 0 :=

h −2c

N

b

N

θf (0)

i

θ−21

. We claim that

(d 0 , 0) is a nondegenerate critical point of Γ ξ

0

. (2.12) Let us compute

∂f

∂ζ i

(0) = a i θ Z

R

N

y i θ−1

(1 + |y| 2 ) N dy = 0 (2.13)

and

2 f

∂ζ i ∂ζ j

(0) =

a i θ(θ − 1)e N if i = j,

0 if i 6= j,

(2.14)

where e N := R

R

N

y 1 θ−2 (1 + |y| 2 ) −N dy. By (2.13) we deduce that (d 0 , 0) is a critical point of Γ, since

∂Γ

∂d (d 0 , 0) = 0 and ∇ ζ Γ(d 0 , 0) = 0.

Moreover

2 Γ

∂d 2 (d 0 , 0) = b N θ(θ − 2)d θ−2 0 f (0) < 0 ,

2 Γ

∂d∂ζ i

(d 0 , 0) = b N θd θ−1 0 ∂f

∂ζ i

(0) = 0,

2 Γ

∂ζ i ∂ζ j (d 0 , 0) = b N d θ 02 f

∂ζ i ∂ζ j (0). (2.15)

Finally (2.12) follows by (2.15) and (2.14).

Proof of Theorem 0.2. It follows from Proposition 2.6 and Proposition 2.5, taking into account Proposition 1.6 and Theorem 2.4.

3 Appendix A

In this appendix we prove Proposition 1.5 and Proposition 1.6. Let K δ,ξ λ be defined in (1.9) and

let Π λ δ,ξ : D λ −→ K δ,ξ λ denote the orthogonal projection.

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Lemma 3.1 It holds

Π λ δ,ξ (u)

λ ≤ kuk λ ∀ u ∈ D λ . Let L λ δ,ξ : K δ,ξ λ −→ K δ,ξ λ be defined by

L λ δ,ξ (φ) = Π λ δ,ξ n

φ − i λ h

(2 − 1)k(ξ 0 )W δ,ξ 2

−2 φ io

.

Lemma 3.2 For any Z ⊂⊂ R N \ {0} there exist C > 0, λ 0 > 0 and δ 0 > 0 such that for any λ ∈ (0, λ 0 ), δ ∈ (0, δ 0 ) and ξ ∈ Z there holds

L λ δ,ξ (φ)

λ ≥ Ckφk ∀ φ ∈ K δ,ξ λ .

Proof. We argue by contradiction. Assume there exist sequences λ n → 0, δ n → 0, ξ n → ξ 6= 0, φ n , ψ n ∈ K δ λ

n

n

n

such that

n k λ

n

= 1, ψ n = L λ δ

n

n

n

n ), kψ n k λ

n

→ 0.

More precisely φ n and ψ n solve φ n − i λ

n

(2 − 1)k(ξ 0 )W δ 2

−2

n

n

φ n  = ψ n + w n , (3.1) where w n = P N

i=0 c i n ψ δ i

n

n

for some real numbers c i n . First of all we claim that

w n −→ 0 in D 1,2 (R N ). (3.2)

If we multiply (3.1) by w n we get for large n kw n k 2 λ

n

= −(2 − 1) Z

R

N

U δ 2

−2

n

n

φ n w n ≤ (2 − 1)

 Z

R

N

U δ 2

n

n

 2/N

n k L

2∗

(R

N

) kw n k L

2∗

(R

N

)

≤ const

 S

 1 − λ n

C N

 −1

kw n k λ

n

and hence kw n k λ

n

≤ const . Therefore for large n

kw n k 2 = Z

R

N

|∇w n | 2 =

N

X

i=0

c i n 2i δ

n

n

k 2 ≤ const .

Multiplying (3.1) by ψ δ j

n

n

, in view of (1.8) we get

 w n , ψ δ j

n

n



λ

n

= −(2 − 1) Z

R

N

U δ 2

−2

n

n

φ n ψ δ j

n

n

= −λ n

Z

R

N

φ n ψ δ j

n

n

|x| 2 = O(λ n )kψ δ j

n

n

k. (3.3)

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On the other hand

 w n , ψ j δ

n

n



λ

n

=

N

X

i=0

c i n 

ψ i δ

n

n

, ψ j δ

n

n



λ

n

=

N

X

i=0

c i n

"

Z

R

N

∇ψ i δ

n

n

· ∇ψ j δ

n

n

− λ n Z

R

N

ψ δ i

n

n

ψ j δ

n

n

|x| 2

#

= kψ j δ

n

n

k 2 c j n − λ n

N

X

i=0

c i n Z

R

N

ψ i δ

n

n

ψ δ j

n

n

|x| 2 and hence from Hardy’s inequality (1.1)

j δ

n

n

k 2 c j n + C N −1 λ nj δ

n

n

k

N

X

i=0

|c i n |kψ δ i

n

n

k

≥  w n , ψ j δ

n

n



λ

n

≥ kψ j δ

n

n

k 2 c j n − C N −1 λ n kψ δ j

n

n

k

N

X

i=0

|c i n |kψ i δ

n

n

k. (3.4)

From (3.3) and (3.4) we deduce that

|c j n |kψ δ j

n

n

k ≤ cλ n 1 +

N

X

i=0

|c i n |kψ i δ

n

n

k

! ,

which implies that c j n kψ j δ

n

n

k → 0 for any j. Therefore (3.2) follows. Now let φ ˜ n (y) := δ

N −2

n

2

φ n (δ n y + ξ n ), k ˜ φ n k = kφ n k ∈ 

1, 1 − λ n /C N

 −1/2 

(3.5) because of (1.3), and

ψ ˜ n (y) := δ

N −2

n

2

ψ n (δ n y + ξ n ), k ˜ ψ n k = kψ n k → 0, (3.6)

˜

w n (y) := δ

N −2

n

2

w nn y + ξ n ), k ˜ w n k = kw n k → 0. (3.7) Up to a subsequence, we can assume that ˜ φ n → φ weakly in D 1,2 (R N ). Given ψ ∈ C c (R N ), let v n (x) = ψ x−ξ δ

n

n

. Note that

kv n k = δ

N −2

n

2

kψk.

Testing (3.1) with v n , we find Z

R

N

∇ ˜ φ n ∇ψ − λ n δ 1−

N

n

2

Z

R

N

φ n v n

|x| 2 − (2 − 1) Z

R

N

U 1,0 2

−2 φ ˜ n ψ

= Z

R

N

∇( ˜ ψ n + ˜ w n ) · ∇ψ − λ n δ 1−

N

n

2

Z

R

N

(ψ n + w n )v n

|x| 2 . (3.8)

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From Hardy inequality we have that

δ 1−

N

n

2

Z

R

N

n v n |

|x| 2 ≤ δ 1−

N

n

2

 Z

R

N

n | 2

|x| 2



12

 Z

R

N

|v n | 2

|x| 2



12

≤ C N −1

 1 − λ n

C N

 −

12

kψk ≤ const (3.9)

and

δ 1−

N

n

2

Z

R

N

n + w n | |v n |

|x| 2 ≤ C N −1n + w n kkψk −→

n→+∞ 0. (3.10)

In view of (3.9) and (3.10), passing to the limit in (3.8) we get that φ is a (weak) solution to

−∆φ = (2 − 1)U 1,0 2

−2 φ in R N . (3.11) Moreover, since φ n ∈ K δ λ

n

n

n

, it is easy to see that φ, ∂U δ,ξ

∂δ

(δ,ξ)=(1,0)

!

= φ, ∂U δ,ξ

∂ξ i

(δ,ξ)=(1,0)

!

= 0, i = 1, . . . , N. (3.12)

By (3.11), (3.12), and Remark 1.4 we deduce that φ = 0. On the other hand, if we multiply (3.1) by φ n we get

1 =kφ n k 2 λ

n

= (2 − 1) Z

R

N

U δ 2

−2

n

n

φ 2 n + (ψ n + w n , φ n ) λ

n

= (2 − 1) Z

R

N

U 1,0 2

−2 φ ˜ 2 n + o(1) hence by letting n → ∞ we find 1 = (2 − 1) R

R

N

U 1,0 2

−2 φ 2 and a contradiction arises.

Proof of Proposition 1.5. First of all we point out that φ solves equation (1.10) if and only if φ is a fixed point of the operator T δ,ξ λ : K δ,ξ λ −→ K δ,ξ λ defined by

T δ,ξ λ (φ) = 

L λ δ,ξ  −1

◦ Π λ δ,ξ ◦ i λ 

k(x) f (W δ,ξ + φ) − f (W δ,ξ ) − f 0 (W δ,ξ ) φ  + [k(x) − k(ξ 0 )] f 0 (W δ,ξ ) φ

+ 

L λ δ,ξ  −1

◦ Π λ δ,ξ 

{i λ [k(x)f (W δ,ξ )] − W δ,ξ } . (3.13) By Lemma 1.3, Lemma 3.1 and Lemma 3.2 we deduce that for some positive constant ¯ c and for any φ, φ 1 , φ 2 ∈ D λ it holds

kT δ,ξ λ (φ)k λ ≤ ¯ c kk(x) f (W δ,ξ + φ) − f (W δ,ξ ) − f 0 (W δ,ξ ) φ k

L

N +22N

+ ¯ c k [k(x) − k(ξ 0 )] f 0 (W δ,ξ ) φk

L

2N

N +2

+ ¯ cki λ [k(x)f (W δ,ξ )] − W δ,ξ k λ (3.14) and

kT δ,ξ λ (φ 1 − φ 2 )k λ ≤ ¯ c kk(x) f (W δ,ξ + φ 1 ) − f (W δ,ξ + φ 2 ) − f 0 (W δ,ξ ) (φ 1 − φ 2 ) k

L

2N N +2

+ ¯ c k [k(x) − k(ξ 0 )] f 0 (W δ,ξ ) (φ 1 − φ 2 )k

L

2N

N +2

. (3.15)

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Let us note that the following inequalities

(a + b) +  s−1

−a s−1 − (s − 1)a s−2 b ≤

C(a s−3 |b| 2 + |b| s−1 ) if s ≥ 3 C |b| s−1 if 2 < s < 3,

(3.16) s

and

(a + b) +  s−1

− a s−1

≤ C|b| s−1 if 1 < s ≤ 2 (3.17) s

where C = C(s) > 0, hold for any b ∈ R, a ∈ R + . From (3.16) s with s = 2 it follows that

f (W δ,ξ + φ) −f (W δ,ξ ) − f 0 (W δ,ξ ) φ ≤

 C

 W

6−N N −2

δ,ξ |φ| 2 + |φ|

N +2N −2



if N ≤ 6 C |φ|

N +2N −2

if N > 6.

(3.18)

From (3.18) and from the inequality

(α + β) γ ≤ 2 γ−1γ + β γ ) for any α, β ≥ 0, γ ≥ 1, we find

f (W δ,ξ + φ) −f (W δ,ξ ) − f 0 (W δ,ξ ) φ

2N N +2

 

  C(W

2(6−N )N (N −2)(N +2)

δ,ξ |φ|

N +24N

+ |φ|

N −22N

) if N ≤ 6 C |φ|

N −22N

if N > 6.

(3.19)

From (3.19) and H¨ older’s inequality we have

k(x)f W δ,ξ + φ − f W δ,ξ  − f 0 W δ,ξ φ

L

2N N +2

 

  C

 kφk

4N N +2

λ + kφk

2N N −2

λ



N +22N

if N ≤ 6 Ckφk

N +2 N −2

λ if N > 6.

(3.20)

Moreover by using H¨ older’s inequality and Lemma 5.7 we get for some constant c > 0 k [k(x) − k(ξ 0 )] f 0 (W δ,ξ ) φk

L

2N

N +2

≤ c kφk λ |ξ − ξ 0 | θ + δ θ . (3.21) From (3.20), (3.21), and (5.18) we deduce that there exists a positive constant ˜ c such that for any φ ∈ ¯ B λ δ,ξ (0, ρ) := {v ∈ K δ,ξ λ : kvk λ ≤ ρ}, ρ ≤ 1,

kT δ,ξ λ (φ)k λ ≤ ˜ c



ρ min{2,

N +2N −2

} + ρ |ξ − ξ 0 | θ + δ θ  + |ξ − ξ 0 | θ + δ θ + h(λ, δ)



, (3.22) where

h(λ, δ) =

 

 

 

 

λδ 2 if N ≥ 5,

λδ 2 log δ if N = 4,

λδ if N = 3.

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Since R

R

N

(W δ,ξ +z) +  2

−2

−W δ,ξ 2

−2

N/2 goes to 0 as z → 0 in D λ by the Dominated Convergence Theorem, we can choose K, δ 0 , and λ 0 such that for any λ ∈ (0, λ 0 ), δ ∈ (0, δ 0 ), and ξ ∈ Z

 

 

 

 

 

 

1

4˜ c − |ξ − ξ 0 | θ − δ θ > 0 and

|ξ − ξ 0 | θ + δ θ + h(λ, δ) ≤ min n

1 4˜ c

1

4˜ c − |ξ − ξ 0 | θ − δ θ  max { 1,

N −24

} , 4c 1

¯ c

o sup

kzk

λ

≤3ρ

λδ,ξ

 R

R

N

(W δ,ξ + z) +  2

−2

− W δ,ξ 2

−2

N/2  2/N

< [S(1−λ/C c(2

−1)kkk

N

)]

L∞1/2

(3.23)

where

¯

ρ λ δ,ξ = 4˜ c |ξ − ξ 0 | θ + δ θ + h(λ, δ). (3.24) From (3.22) and (3.23) we find

kT δ,ξ λ (φ)k λ ≤ ¯ ρ λ δ,ξ for any φ ∈ ¯ B δ,ξ λ (0, ¯ ρ λ δ,ξ ).

In particular T δ,ξ λ maps B δ,ξ λ (0, ¯ ρ λ δ,ξ ) into itself; in order to prove that it is a contraction there we have also to estimate T δ,ξ λ1 − φ 2 ), i.e. the right hand side in (3.15). By H¨ older inequality and (3.23) we have

kk(x)f (W δ,ξ + φ 1 ) − f (W δ,ξ + φ 2 ) − f 0 (W δ,ξ ) (φ 1 − φ 2 )k

L

N +22N

≤ kkk L

Z 1 0

 d

dt f (W δ,ξ + φ 2 + t(φ 1 − φ 2 )



− f 0 (W δ,ξ )(φ 1 − φ 2 ) L

2N N +2

≤ kkk L

Z 1 0

f 0 (W δ,ξ + φ 2 + t(φ 1 − φ 2 )) − f 0 (W δ,ξ )(φ 1 − φ 2 ) L

N +22N

≤ kkk L

1 − φ 2 k L

2∗

sup

kzk

λ

≤3 ¯ ρ

λδ,ξ

kf 0 (W δ,ξ + z) − f 0 (W δ,ξ )k L

N/2

≤ 1

4¯ c kφ 1 − φ 2 k λ . (3.25) Moreover from (3.21) and (3.23) we have

k [k(x) − k(ξ 0 )] f 0 (W δ,ξ ) (φ 1 − φ 2 )k

L

2N

N +2

≤ c 1 − φ 2 k λ |ξ − ξ 0 | θ + δ θ  ≤ 1

4¯ c kφ 1 − φ 2 k λ . (3.26) From (3.15), (3.25), and (3.26) we obtain

kT δ,ξ λ (φ 1 − φ 2 )k λ ≤ 1

2 kφ 1 − φ 2 k λ for any φ 1 , φ 2 ∈ B λ δ,ξ (0, ¯ ρ λ δ,ξ )

namely T δ,ξ λ is a contraction in B δ,ξ λ (0, ¯ ρ λ δ,ξ ) and hence T δ,ξ λ has a unique fixed point φ λ δ,ξ in B δ,ξ λ (0, ¯ ρ λ δ,ξ ). In particular, in view of (3.24), φ λ δ,ξ satisfies estimate (1.11).

Lemma 3.3 There exist Z ⊂⊂ R N such that ξ 0 ∈ Z, λ 0 > 0 and δ 0 > 0 such that for any

λ ∈ (0, λ 0 ), the function (δ, ξ) 7→ φ λ δ,ξ given by Proposition 1.5 is of class C 1 on (0, δ 0 ) × Z.

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Proof. From (1.10) it follows that for any v ∈ K δ,ξ λ

W δ,ξ + φ λ δ,ξ − i λ (k(x)f (W δ,ξ + φ λ δ,ξ )), v) λ = 0 i.e.

(W δ,ξ + φ λ δ,ξ , v) λ − Z

R

N

k(x)f (W δ,ξ + φ λ δ,ξ )v dx = 0, which can be written in term of the functional J λ as

(J λ 0 (W δ,ξ + φ λ δ,ξ ), v) λ = 0 for any v ∈ K δ,ξ λ

where J λ 0 (u) denotes the Fr´ echet derivative of J λ at u (identified with an element of D λ through the canonical identification of the Hilbert space D λ with its dual). Hence φ λ δ,ξ satisfies

Π λ δ,ξ J λ 0 (W δ,ξ + φ λ δ,ξ ) = 0. (3.27) For λ fixed consider the map

R + × R N × D λ −→ D λ

(δ, ξ, φ) 7−→ Π λ δ,ξ J λ 0 (W δ,ξ + φ). (3.28) Let us remark that J λ ∈ C 2 (D λ , R) and the map (δ, ξ) 7→ W δ,ξ which parametrizes the manifold of the solutions to the limit problem is of class C 2 . Morover the projection map Π λ δ,ξ can be written in the form

Π λ δ,ξ (u) = u −

N

X

j=0



u, Υ j λ,δ,ξj λ,δ,ξ k λ



λ

Υ j λ,δ,ξj λ,δ,ξ k λ where

Υ 0 λ,δ,ξ = ψ δ,ξ 0δ,ξ 0 k λ , Υ j λ,δ,ξ = ψ δ,ξ j

δ,ξ j k λ

j−1

X

i=0

 ψ δ,ξ j

j δ,ξ k λ , Υ i λ,δ,ξi λ,δ,ξ k λ



λ

Υ i λ,δ,ξ

i λ,δ,ξ k λ , j = 1, . . . , N. (3.29) Note that Υ j λ,δ,ξ , j = 0, 1, . . . , N generate the linear space span{ψ δ,ξ j : j = 0, 1, . . . , N }, solve equation (1.8), and satisfy 

Υ j λ,δ,ξ , Υ i λ,δ,ξ 

λ = 0, i 6= j. It is easy to verify that (δ, ξ) 7→ Υ j λ,δ,ξ is a C 1 −map, and consequently the projection map Π λ δ,ξ is of class C 1 . Hence we deduce that the map defined in (3.28) is of class C 1 , as it is shown in the diagram below

(δ, ξ, φ) C

2

7−→ W δ,ξ 7−→ W C

δ,ξ + φ C

1

7−→ J λ 0 (W δ,ξ + φ) C

1

7−→ Π λ δ,ξ J λ 0 (W δ,ξ + φ).

From (3.27), the regularity of the map defined in (3.28), and the Implicit Function Theorem the

statement follows.

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Lemma 3.4 J λ 00 (W δ,ξ + φ λ δ,ξ )u = L λ δ,ξλ δ,ξ u) + kuk λ o(1) as δ, λ, |ξ − ξ 0 | → 0.

Proof. We have that for any v ∈ D λ

(J λ 00 (W δ,ξ + φ λ δ,ξ )u, v) λ − (L λ δ,ξλ δ,ξ u), v) λ = (J λ 00 (W δ,ξ + φ λ δ,ξλ δ,ξ u, Π λ δ,ξ v) λ

− (L λ δ,ξλ δ,ξ u), Π λ δ,ξ v) λ + (J λ 00 (W δ,ξ + φ λ δ,ξ )u, v − Π λ δ,ξ v) λ

+ (J λ 00 (W δ,ξ + φ λ δ,ξ )(u − Π λ δ,ξ u, Π λ δ,ξ v) λ . (3.30) For simplicity of notation, let us set f δ,ξ j := Υ

j λ,δ,ξ

jλ,δ,ξ

k

λ

. Note that by H¨ older inequality (J λ 00 (W δ,ξ + φ λ δ,ξ )u, v − Π λ δ,ξ v) λ

=

N

X

j=0

v, f δ,ξ j 

λ



u, f δ,ξ j 

λ − (2 − 1) Z

R

N

k(x)(W δ,ξ + φ λ δ,ξ ) 2

−2 f δ,ξ j u



=

N

X

j=0

v, f δ,ξ j 

λ



− (2 − 1) Z

R

N

k(x)[(W δ,ξ + φ λ δ,ξ ) 2

−2 − W δ,ξ 2

−2 ]f δ,ξ j u

− (2 − 1) Z

R

N

[k(x) − k(ξ 0 )]W δ,ξ 2

−2 f δ,ξ j u − λ Z

R

N

f δ,ξ j u

|x| 2



≤ constkuk λ kvk λ λ + k(k(x) − k(ξ 0 ))W δ,ξ 2

−2 k L

N/2

+ k(W δ,ξ + φ λ δ,ξ ) 2

−2 − W δ,ξ 2

−2 k L

N/2

.

Hence from (3.16) s and (3.17) s with s = 2 − 1 and Lemma 5.7, we get (J λ 00 (W δ,ξ + φ λ δ,ξ )u,v − Π λ δ,ξ v) λ

≤ constkuk λ kvk λ λ + |ξ − ξ 0 | ϑ + δ ϑ + kφ λ δ,ξ k λ + kφ λ δ,ξ k 4/(N −2) λ . (3.31) Arguing in a similar way we can show that

(J λ 00 (W δ,ξ + φ λ δ,ξ )(u − Π λ δ,ξ u), Π λ δ,ξ v) λ

≤ constkuk λ kvk λ λ + |ξ − ξ 0 | ϑ + δ ϑ + kφ λ δ,ξ k λ + kφ λ δ,ξ k 4/(N −2) λ 

(3.32) and

(J λ 00 (W δ,ξ + φ λ δ,ξλ δ,ξ u,Π λ δ,ξ v) λ − (L λ δ,ξλ δ,ξ u), Π λ δ,ξ v) λ

= −(2 − 1)

 Z

R

N

k(x)[(W δ,ξ + φ λ δ,ξ ) 2

−2 − W δ,ξ 2

−2λ δ,ξλ δ,ξ v +

Z

R

N

(k(x) − k(ξ 0 ))W δ,ξ 2

−2 Π λ δ,ξλ δ,ξ v



≤ constkuk λ kvk λ |ξ − ξ 0 | ϑ + δ ϑ + kφ λ δ,ξ k λ + kφ λ δ,ξ k 4/(N −2) λ . (3.33)

The lemma follows from (3.30), (3.31), (3.32), and (3.33).

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Lemma 3.5 There holds

∂φ λ δ,ξ

∂δ λ

=

 

 

 

 

δ −1 O λδ + |ξ − ξ 0 | θ + δ θ + kφ λ δ,ξ k min{1,4/(N −2)}

λ

 if N ≥ 5, δ −1 O λδp| log δ| + |ξ − ξ 0 | θ + δ θ + kφ λ δ,ξ k λ 

if N = 4, δ −1 O λδ 1/2 + |ξ − ξ 0 | θ + δ θ + kφ λ δ,ξ k λ 

if N = 3,

(3.34)

and for N ≥ 3 and i = 1, . . . , N

∂φ λ δ,ξ

∂ξ i

λ

= δ −1 O



λδ + |ξ − ξ 0 | θ + δ θ + kφ λ δ,ξ k min{1,4/(N −2)}

λ



. (3.35)

Proof. Let us first note that from standard calculations, it is easy to verify that for some positiver constants C 0 (N, k(ξ 0 )) and C 1 (N, k(ξ 0 ))

δ,ξ 0 k = C 0 (N, k(ξ 0 ))δ −1 , kψ δ,ξ j k = C 1 (N, k(ξ 0 ))δ −1 , j = 1, . . . , N,

∂ψ 0

∂δ ,

∂ψ 0

∂ξ i ,

∂ψ j

∂δ ,

∂ψ j

∂ξ i

= O(δ −2 ). (3.36)

From (3.27) it follows that there exist N + 1 real valued C 1 -function α j (λ, δ, ξ) such that J λ 0 (W δ,ξ + φ λ δ,ξ ) =

N

X

j=0

α j (λ, δ, ξ) Υ j λ,δ,ξj λ,δ,ξ k λ , where Υ j λ,δ,ξ are defined in (3.29). Since

α j (λ, δ, ξ) +

N

X

i=0 i6=j

α i (λ, δ, ξ) Υ i λ,δ,ξ

i λ,δ,ξ k λ , Υ j λ,δ,ξj λ,δ,ξ k λ

!

λ

=



J λ 0 (W δ,ξ + φ λ δ,ξ ), Υ j λ,δ,ξj λ,δ,ξ k λ



λ

= − λ

j λ,δ,ξ k λ Z

R

N

W δ,ξ Υ j λ,δ,ξ

|x| 2 dx

− Z

R

N

k(x)((W δ,ξ + φ λ δ,ξ ) 2

−1 − W δ,ξ 2

−1 ) Υ j λ,δ,ξ

j λ,δ,ξ k λ dx − Z

R

N

(k(x) − k(ξ 0 ))W δ,ξ 2

−1 Υ j λ,δ,ξj λ,δ,ξ k λ dx, using (3.36), Lemma 5.2, Lemma 5.5, (3.29), and (3.20) we deduce that for any j = 0, 1, . . . , N

j (λ, δ, ξ)| =

 

 

O λδ 2 + |ξ − ξ 0 | θ + δ θ + kφ λ δ,ξ k λ 

if N ≥ 5, O λδ 2 | log δ| + |ξ − ξ 0 | θ + δ θ + kφ λ δ,ξ k λ 

if N = 4, O λδ + |ξ − ξ 0 | θ + δ θ + kφ λ δ,ξ k λ 

if N = 3.

(3.37)

The function (λ, δ, ξ) 7→ (φ λ δ,ξ , α 0 (λ, δ, ξ), . . . , α N (λ, δ, ξ)) is implicitly given by H(δ, ξ, φ, α, λ) = 0 where

H : (0, δ 0 ) × R N × D λ × R N +1 × (0, λ 0 ) → D λ × R N +1 (δ, ξ, φ, α, λ) 7→



J λ 0 (W δ,ξ + φ) −

N

X

j=0

α j Υ j λ,δ,ξj λ,δ,ξ k λ ,



φ, Υ j λ,δ,ξj λ,δ,ξ k λ

 j=0,...,N λ



.

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Since

∂H 1

∂(φ, α) (φ,α)

 u β



= J λ 00 (W δ,ξ + φ)u −

N

X

j=0

β j

Υ j λ,δ,ξj λ,δ,ξ k λ

∂H 2

∂(φ, α) (φ,α)

 u β



=



u, Υ j λ,δ,ξj λ,δ,ξ k λ

 j=0,...,N λ

,

in view of Lemma 3.4 and (3.31) we find for any (u, β) ∈ D λ × R N +1

∂H

∂(φ, α)

λδ,ξ

,α(λ,δ,ξ))

 u β



2

=

J λ 00 (W δ,ξ + φ λ δ,ξ )u −

N

X

j=0

β j

Υ j λ,δ,ξj λ,δ,ξ k λ

2

λ

+

N

X

j=0



u, Υ j λ,δ,ξj λ,δ,ξ k λ

 2 λ

=

J λ 00 (W δ,ξ + φ λ δ,ξ )u

2 λ +

N

X

j=0

β j 2 + ku − Π λ δ,ξ uk 2 − 2

N

X

j=0

β j



J λ 00 (W δ,ξ + φ λ δ,ξ )u, Υ j λ,δ,ξj λ,δ,ξ k λ



λ

≥ (kL λ δ,ξλ δ,ξ u)k − kuk λ o(1)) 2 + |β| 2 + ku − Π λ δ,ξ uk 2 − 2

N

X

j=0

j |kuk λ o(1).

Hence from Lemma 3.2 we obtain for λ, δ, |ξ − ξ 0 | small

∂H

∂(φ, α)

λδ,ξ

,α(λ,δ,ξ))

 u β



2

≥ const

 u β



2

.

Therefore there exist δ 0 > 0, λ 0 > 0, a small neighbourhood Z of ξ 0 , and a positive constant C , such that for any δ ∈ (0, δ 0 ), λ ∈ (0, λ 0 ), ξ ∈ Z,

∂H

∂(φ, α)

−1

λδ,ξ

,α(λ,δ,ξ))

≤ C .

From the Implicit Function Theorem, we have that

 ∂ δ φ λ δ,ξ

δ α(λ, δ, ξ)



= − ∂H

∂(φ, α)

−1

λδ,ξ

,α(λ,δ,ξ))

× ∂H

∂δ

λ

δ,ξ

,α(λ,δ,ξ))

and hence

∂φ λ δ,ξ

∂δ λ

≤ const

∂H

∂δ

λδ,ξ

,α(λ,δ,ξ))

= const



J λ 00 (W δ,ξ + φ λ δ,ξ0 δ,ξ

N

X

j=0

α j (λ, δ, ξ) ∂

∂δ

Υ j λ,δ,ξj λ,δ,ξ k λ

+

N

X

j=0

 φ λ δ,ξ , ∂

∂δ

Υ j λ,δ,ξj λ,δ,ξ k λ



λ

.

(3.38)

Riferimenti

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