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ARITHMETICAL RANK OF CERTAIN SEGRE PRODUCTS

Matteo Varbaro

Dipartimento di Matematica Universit´a di Genova

(2)

What is the arithmetical rank?

LetR be a Noetherian commutative ring with 1, andI ⊆ R an ideal.

The arirthmetical rank of I is

ara(I )= min{r : ∃ a1, . . . , ar ∈ R for which

a1, . . . , ar = I }

If R = K [x1, . . . , xn] then ara(I ) denotesthe least number of hypersurfaces of An which define set-theoretically V(I ) ⊆ An.

If R and I are graded the homogeneous arithmetical rank of I is arah(I )= min{r : ∃ a1, . . . , ar ∈ R homogeneouss.t.

a1, . . . , ar = I }

When R = K [x0, . . . , xN], then arah(I ) is theleast number of hypersurfaces of PN which define set-theoretically V+(I ) ⊆ PN.

Clearlyara(I ) ≤ arah(I ).

(3)

What is the arithmetical rank?

LetR be a Noetherian commutative ring with 1, andI ⊆ R an ideal.

The arirthmetical rank of I is

ara(I )= min{r : ∃ a1, . . . , ar ∈ R for which

a1, . . . , ar = I }

If R = K [x1, . . . , xn] then ara(I ) denotesthe least number of hypersurfaces of An which define set-theoretically V(I ) ⊆ An.

If R and I are graded the homogeneous arithmetical rank of I is arah(I )= min{r : ∃ a1, . . . , ar ∈ R homogeneouss.t.

a1, . . . , ar = I }

When R = K [x0, . . . , xN], then arah(I ) is theleast number of hypersurfaces of PN which define set-theoretically V+(I ) ⊆ PN.

Clearlyara(I ) ≤ arah(I ).

(4)

What is the arithmetical rank?

LetR be a Noetherian commutative ring with 1, andI ⊆ R an ideal.

The arirthmetical rank of I is

ara(I )= min{r : ∃ a1, . . . , ar∈ R for which

a1, . . . , ar = I }

If R = K [x1, . . . , xn] then ara(I ) denotesthe least number of hypersurfaces of An which define set-theoretically V(I ) ⊆ An.

If R and I are graded the homogeneous arithmetical rank of I is arah(I )= min{r : ∃ a1, . . . , ar ∈ R homogeneouss.t.

a1, . . . , ar = I }

When R = K [x0, . . . , xN], then arah(I ) is theleast number of hypersurfaces of PN which define set-theoretically V+(I ) ⊆ PN.

Clearlyara(I ) ≤ arah(I ).

(5)

What is the arithmetical rank?

LetR be a Noetherian commutative ring with 1, andI ⊆ R an ideal.

The arirthmetical rank of I is

ara(I )= min{r : ∃ a1, . . . , ar∈ R for which

a1, . . . , ar = I }

If R = K [x1, . . . , xn] then ara(I ) denotesthe least number of hypersurfaces of An which define set-theoretically V(I ) ⊆ An.

If R and I are graded the homogeneous arithmetical rank of I is arah(I )= min{r : ∃ a1, . . . , ar ∈ R homogeneouss.t.

a1, . . . , ar = I }

When R = K [x0, . . . , xN], then arah(I ) is theleast number of hypersurfaces of PN which define set-theoretically V+(I ) ⊆ PN.

Clearlyara(I ) ≤ arah(I ).

(6)

What is the arithmetical rank?

LetR be a Noetherian commutative ring with 1, andI ⊆ R an ideal.

The arirthmetical rank of I is

ara(I )= min{r : ∃ a1, . . . , ar∈ R for which

a1, . . . , ar = I }

If R = K [x1, . . . , xn] then ara(I ) denotesthe least number of hypersurfaces of An which define set-theoretically V(I ) ⊆ An.

If R and I are graded the homogeneous arithmetical rank of I is

arah(I )= min{r : ∃ a1, . . . , ar ∈ R homogeneouss.t.

a1, . . . , ar = I }

When R = K [x0, . . . , xN], then arah(I ) is theleast number of hypersurfaces of PN which define set-theoretically V+(I ) ⊆ PN.

Clearlyara(I ) ≤ arah(I ).

(7)

What is the arithmetical rank?

LetR be a Noetherian commutative ring with 1, andI ⊆ R an ideal.

The arirthmetical rank of I is

ara(I )= min{r : ∃ a1, . . . , ar∈ R for which

a1, . . . , ar = I }

If R = K [x1, . . . , xn] then ara(I ) denotesthe least number of hypersurfaces of An which define set-theoretically V(I ) ⊆ An.

If R and I are graded the homogeneous arithmetical rank of I is arah(I )= min{r : ∃ a1, . . . , ar ∈ R homogeneouss.t.

a1, . . . , ar = I }

When R = K [x0, . . . , xN], then arah(I ) is theleast number of hypersurfaces of PN which define set-theoretically V+(I ) ⊆ PN.

Clearlyara(I ) ≤ arah(I ).

(8)

What is the arithmetical rank?

LetR be a Noetherian commutative ring with 1, andI ⊆ R an ideal.

The arirthmetical rank of I is

ara(I )= min{r : ∃ a1, . . . , ar∈ R for which

a1, . . . , ar = I }

If R = K [x1, . . . , xn] then ara(I ) denotesthe least number of hypersurfaces of An which define set-theoretically V(I ) ⊆ An.

If R and I are graded the homogeneous arithmetical rank of I is arah(I )= min{r : ∃ a1, . . . , ar ∈ R homogeneouss.t.

a1, . . . , ar = I }

When R = K [x0, . . . , xN], then arah(I ) is theleast number of hypersurfaces of PN which define set-theoretically V+(I ) ⊆ PN.

Clearlyara(I ) ≤ arah(I ).

(9)

What is the arithmetical rank?

LetR be a Noetherian commutative ring with 1, andI ⊆ R an ideal.

The arirthmetical rank of I is

ara(I )= min{r : ∃ a1, . . . , ar∈ R for which

a1, . . . , ar = I }

If R = K [x1, . . . , xn] then ara(I ) denotesthe least number of hypersurfaces of An which define set-theoretically V(I ) ⊆ An.

If R and I are graded the homogeneous arithmetical rank of I is arah(I )= min{r : ∃ a1, . . . , ar ∈ R homogeneouss.t.

a1, . . . , ar = I }

When R = K [x0, . . . , xN], then arah(I ) is theleast number of hypersurfaces of PN which define set-theoretically V+(I ) ⊆ PN.

Clearlyara(I ) ≤ arah(I ).

(10)

An example

I = (x0x2, x0x3, x1x2, x1x3) = (x0, x1) ∩ (x2, x3) ⊆ K [x0, x1, x2, x3]

I = I =

J whereJ = (x0x2, x1x3, x0x3+ x1x2), in fact (x0x3)2 = x0x3· (x0x3+ x1x2) − x0x2·x1x3 ∈ J Therefore ara(I ) ≤ arah(I ) ≤3. On the other side Krull’s principal ideal theorem impliesara(I ) ≥ ht(I )=2. But V+(I ) ⊆ P3is a disconnected projective scheme of dimension 1. This implies, in various ways, thatara(I ) > ht(I ). So

ara(I ) = arah(I ) = 3

(11)

An example

I = (x0x2, x0x3, x1x2, x1x3) = (x0, x1) ∩ (x2, x3) ⊆ K [x0, x1, x2, x3]

I = I =

J whereJ = (x0x2, x1x3, x0x3+ x1x2), in fact (x0x3)2 = x0x3· (x0x3+ x1x2) − x0x2·x1x3 ∈ J Therefore ara(I ) ≤ arah(I ) ≤3. On the other side Krull’s principal ideal theorem impliesara(I ) ≥ ht(I )=2. But V+(I ) ⊆ P3is a disconnected projective scheme of dimension 1. This implies, in various ways, thatara(I ) > ht(I ). So

ara(I ) = arah(I ) = 3

(12)

An example

I = (x0x2, x0x3, x1x2, x1x3) = (x0, x1) ∩ (x2, x3) ⊆ K [x0, x1, x2, x3]

I = I =

J whereJ = (x0x2, x1x3, x0x3+ x1x2),

in fact (x0x3)2 = x0x3· (x0x3+ x1x2) − x0x2·x1x3 ∈ J Therefore ara(I ) ≤ arah(I ) ≤3. On the other side Krull’s principal ideal theorem impliesara(I ) ≥ ht(I )=2. But V+(I ) ⊆ P3is a disconnected projective scheme of dimension 1. This implies, in various ways, thatara(I ) > ht(I ). So

ara(I ) = arah(I ) = 3

(13)

An example

I = (x0x2, x0x3, x1x2, x1x3) = (x0, x1) ∩ (x2, x3) ⊆ K [x0, x1, x2, x3]

I = I =

J whereJ = (x0x2, x1x3, x0x3+ x1x2), in fact (x0x3)2 = x0x3· (x0x3+ x1x2) − x0x2·x1x3 ∈ J

Therefore ara(I ) ≤ arah(I ) ≤3. On the other side Krull’s principal ideal theorem impliesara(I ) ≥ ht(I )=2. But V+(I ) ⊆ P3is a disconnected projective scheme of dimension 1. This implies, in various ways, thatara(I ) > ht(I ). So

ara(I ) = arah(I ) = 3

(14)

An example

I = (x0x2, x0x3, x1x2, x1x3) = (x0, x1) ∩ (x2, x3) ⊆ K [x0, x1, x2, x3]

I = I =

J whereJ = (x0x2, x1x3, x0x3+ x1x2), in fact (x0x3)2 = x0x3· (x0x3+ x1x2) − x0x2·x1x3 ∈ J Therefore ara(I ) ≤ arah(I ) ≤3.

On the other side Krull’s principal ideal theorem impliesara(I ) ≥ ht(I )=2. But V+(I ) ⊆ P3is a disconnected projective scheme of dimension 1. This implies, in various ways, thatara(I ) > ht(I ). So

ara(I ) = arah(I ) = 3

(15)

An example

I = (x0x2, x0x3, x1x2, x1x3) = (x0, x1) ∩ (x2, x3) ⊆ K [x0, x1, x2, x3]

I = I =

J whereJ = (x0x2, x1x3, x0x3+ x1x2), in fact (x0x3)2 = x0x3· (x0x3+ x1x2) − x0x2·x1x3 ∈ J Therefore ara(I ) ≤ arah(I ) ≤3. On the other side Krull’s principal ideal theorem impliesara(I ) ≥ ht(I )=2.

But V+(I ) ⊆ P3is a disconnected projective scheme of dimension 1. This implies, in various ways, thatara(I ) > ht(I ). So

ara(I ) = arah(I ) = 3

(16)

An example

I = (x0x2, x0x3, x1x2, x1x3) = (x0, x1) ∩ (x2, x3) ⊆ K [x0, x1, x2, x3]

I = I =

J whereJ = (x0x2, x1x3, x0x3+ x1x2), in fact (x0x3)2 = x0x3· (x0x3+ x1x2) − x0x2·x1x3 ∈ J Therefore ara(I ) ≤ arah(I ) ≤3. On the other side Krull’s principal ideal theorem impliesara(I ) ≥ ht(I )=2.

But V+(I ) ⊆ P3is a disconnected projective scheme of dimension 1.

This implies, in various ways, thatara(I ) > ht(I ). So

ara(I ) = arah(I ) = 3

(17)

An example

I = (x0x2, x0x3, x1x2, x1x3) = (x0, x1) ∩ (x2, x3) ⊆ K [x0, x1, x2, x3]

I = I =

J whereJ = (x0x2, x1x3, x0x3+ x1x2), in fact (x0x3)2 = x0x3· (x0x3+ x1x2) − x0x2·x1x3 ∈ J Therefore ara(I ) ≤ arah(I ) ≤3. On the other side Krull’s principal ideal theorem impliesara(I ) ≥ ht(I )=2.

But V+(I ) ⊆ P3is a disconnected projective scheme of dimension 1.

This implies, in various ways, thatara(I ) > ht(I ).

So

ara(I ) = arah(I ) = 3

(18)

An example

I = (x0x2, x0x3, x1x2, x1x3) = (x0, x1) ∩ (x2, x3) ⊆ K [x0, x1, x2, x3]

I = I =

J whereJ = (x0x2, x1x3, x0x3+ x1x2), in fact (x0x3)2 = x0x3· (x0x3+ x1x2) − x0x2·x1x3 ∈ J Therefore ara(I ) ≤ arah(I ) ≤3. On the other side Krull’s principal ideal theorem impliesara(I ) ≥ ht(I )=2.

But V+(I ) ⊆ P3is a disconnected projective scheme of dimension 1.

This implies, in various ways, thatara(I ) > ht(I ). So

ara(I ) = arah(I ) = 3

(19)

Known and unknown things about the arithmetical rank

-S = K [x0, . . . , xN], I ⊆ S homogeneous ideal

arah(I ) ≤N + 1(Fairly easy to show) (Eisenbud-Evans)If ht(I ) ≤ N, then arah(I ) ≤N

Conjecture: V+(I ) connected of dimension at least 1. Then arah(I ) ≤N − 1

This conjecture iscompletely open, also in the case in which I is the ideal of K [x0, x1, x2, x3] given by the kernel of:

x0 7→ u4, x17→ u3t, x2 7→ ut3, x3 7→ t4

(20)

Known and unknown things about the arithmetical rank

-S = K [x0, . . . , xN], I ⊆ S homogeneous ideal

arah(I ) ≤N + 1(Fairly easy to show) (Eisenbud-Evans)If ht(I ) ≤ N, then arah(I ) ≤N

Conjecture: V+(I ) connected of dimension at least 1. Then arah(I ) ≤N − 1

This conjecture iscompletely open, also in the case in which I is the ideal of K [x0, x1, x2, x3] given by the kernel of:

x0 7→ u4, x17→ u3t, x2 7→ ut3, x3 7→ t4

(21)

Known and unknown things about the arithmetical rank

-S = K [x0, . . . , xN], I ⊆ S homogeneous ideal

arah(I ) ≤N + 1(Fairly easy to show)

(Eisenbud-Evans)If ht(I ) ≤ N, then arah(I ) ≤N

Conjecture: V+(I ) connected of dimension at least 1. Then arah(I ) ≤N − 1

This conjecture iscompletely open, also in the case in which I is the ideal of K [x0, x1, x2, x3] given by the kernel of:

x0 7→ u4, x17→ u3t, x2 7→ ut3, x3 7→ t4

(22)

Known and unknown things about the arithmetical rank

-S = K [x0, . . . , xN], I ⊆ S homogeneous ideal

arah(I ) ≤N + 1(Fairly easy to show) (Eisenbud-Evans)If ht(I ) ≤ N, then arah(I ) ≤N

Conjecture: V+(I ) connected of dimension at least 1. Then arah(I ) ≤N − 1

This conjecture iscompletely open, also in the case in which I is the ideal of K [x0, x1, x2, x3] given by the kernel of:

x0 7→ u4, x17→ u3t, x2 7→ ut3, x3 7→ t4

(23)

Known and unknown things about the arithmetical rank

-S = K [x0, . . . , xN], I ⊆ S homogeneous ideal

arah(I ) ≤N + 1(Fairly easy to show) (Eisenbud-Evans)If ht(I ) ≤ N, then arah(I ) ≤N

Conjecture:

V+(I ) connected of dimension at least 1. Then arah(I ) ≤N − 1

This conjecture iscompletely open, also in the case in which I is the ideal of K [x0, x1, x2, x3] given by the kernel of:

x0 7→ u4, x17→ u3t, x2 7→ ut3, x3 7→ t4

(24)

Known and unknown things about the arithmetical rank

-S = K [x0, . . . , xN], I ⊆ S homogeneous ideal

arah(I ) ≤N + 1(Fairly easy to show) (Eisenbud-Evans)If ht(I ) ≤ N, then arah(I ) ≤N

Conjecture: V+(I ) connected of dimension at least 1.

Then arah(I ) ≤N − 1

This conjecture iscompletely open, also in the case in which I is the ideal of K [x0, x1, x2, x3] given by the kernel of:

x0 7→ u4, x17→ u3t, x2 7→ ut3, x3 7→ t4

(25)

Known and unknown things about the arithmetical rank

-S = K [x0, . . . , xN], I ⊆ S homogeneous ideal

arah(I ) ≤N + 1(Fairly easy to show) (Eisenbud-Evans)If ht(I ) ≤ N, then arah(I ) ≤N

Conjecture: V+(I ) connected of dimension at least 1. Then arah(I ) ≤N − 1

This conjecture iscompletely open, also in the case in which I is the ideal of K [x0, x1, x2, x3] given by the kernel of:

x0 7→ u4, x17→ u3t, x2 7→ ut3, x3 7→ t4

(26)

Known and unknown things about the arithmetical rank

-S = K [x0, . . . , xN], I ⊆ S homogeneous ideal

arah(I ) ≤N + 1(Fairly easy to show) (Eisenbud-Evans)If ht(I ) ≤ N, then arah(I ) ≤N

Conjecture: V+(I ) connected of dimension at least 1. Then arah(I ) ≤N − 1

This conjecture iscompletely open,

also in the case in which I is the ideal of K [x0, x1, x2, x3] given by the kernel of:

x0 7→ u4, x17→ u3t, x2 7→ ut3, x3 7→ t4

(27)

Known and unknown things about the arithmetical rank

-S = K [x0, . . . , xN], I ⊆ S homogeneous ideal

arah(I ) ≤N + 1(Fairly easy to show) (Eisenbud-Evans)If ht(I ) ≤ N, then arah(I ) ≤N

Conjecture: V+(I ) connected of dimension at least 1. Then arah(I ) ≤N − 1

This conjecture iscompletely open, also in the case in which I is the ideal of K [x0, x1, x2, x3] given by the kernel of:

x0 7→ u4, x17→ u3t, x2 7→ ut3, x3 7→ t4

(28)

Known and unknown things about the arithmetical rank

-S = K [x0, . . . , xN], I ⊆ S homogeneous ideal

arah(I ) ≤N + 1(Fairly easy to show) (Eisenbud-Evans)If ht(I ) ≤ N, then arah(I ) ≤N

Conjecture: V+(I ) connected of dimension at least 1. Then arah(I ) ≤N − 1

This conjecture iscompletely open, also in the case in which I is the ideal of K [x0, x1, x2, x3] given by the kernel of:

x07→ u4, x17→ u3t, x27→ ut3, x3 7→ t4

(29)

Goal of the talk

-f ⊆ R = K [Pn] = K [x0, . . . , xn]graded polynomial of degree d -X = V+(f ) ⊆ Pn (smooth) hypersurface

-Y = X × Pm ⊆ PN Segre embedding(so that N = nm + n + m) -I ⊆ S = K [PN] = K [zij :i = 0, . . . , n; j = 0, . . . , m]the idealdefining Y

WHAT CAN WE SAY ABOUT arah(I )?

The case X = Pn has been already settled by Bruns and Schw¨anzl.

(30)

Goal of the talk

-f ⊆ R = K [Pn] = K [x0, . . . , xn]graded polynomial of degree d

-X = V+(f ) ⊆ Pn (smooth) hypersurface

-Y = X × Pm ⊆ PN Segre embedding(so that N = nm + n + m) -I ⊆ S = K [PN] = K [zij :i = 0, . . . , n; j = 0, . . . , m]the idealdefining Y

WHAT CAN WE SAY ABOUT arah(I )?

The case X = Pn has been already settled by Bruns and Schw¨anzl.

(31)

Goal of the talk

-f ⊆ R = K [Pn] = K [x0, . . . , xn]graded polynomial of degree d -X = V+(f ) ⊆ Pn (smooth) hypersurface

-Y = X × Pm ⊆ PN Segre embedding(so that N = nm + n + m) -I ⊆ S = K [PN] = K [zij :i = 0, . . . , n; j = 0, . . . , m]the idealdefining Y

WHAT CAN WE SAY ABOUT arah(I )?

The case X = Pn has been already settled by Bruns and Schw¨anzl.

(32)

Goal of the talk

-f ⊆ R = K [Pn] = K [x0, . . . , xn]graded polynomial of degree d -X = V+(f ) ⊆ Pn (smooth) hypersurface

-Y = X × Pm ⊆ PN Segre embedding(so that N = nm + n + m)

-I ⊆ S = K [PN] = K [zij :i = 0, . . . , n; j = 0, . . . , m]the idealdefining Y

WHAT CAN WE SAY ABOUT arah(I )?

The case X = Pn has been already settled by Bruns and Schw¨anzl.

(33)

Goal of the talk

-f ⊆ R = K [Pn] = K [x0, . . . , xn]graded polynomial of degree d -X = V+(f ) ⊆ Pn (smooth) hypersurface

-Y = X × Pm ⊆ PN Segre embedding(so that N = nm + n + m) -I ⊆ S = K [PN] = K [zij :i = 0, . . . , n; j = 0, . . . , m]the idealdefining Y

WHAT CAN WE SAY ABOUT arah(I )?

The case X = Pn has been already settled by Bruns and Schw¨anzl.

(34)

Goal of the talk

-f ⊆ R = K [Pn] = K [x0, . . . , xn]graded polynomial of degree d -X = V+(f ) ⊆ Pn (smooth) hypersurface

-Y = X × Pm ⊆ PN Segre embedding(so that N = nm + n + m) -I ⊆ S = K [PN] = K [zij :i = 0, . . . , n; j = 0, . . . , m]the idealdefining Y

WHAT CAN WE SAY ABOUT arah(I )?

The case X = Pn has been already settled by Bruns and Schw¨anzl.

(35)

Goal of the talk

-f ⊆ R = K [Pn] = K [x0, . . . , xn]graded polynomial of degree d -X = V+(f ) ⊆ Pn (smooth) hypersurface

-Y = X × Pm ⊆ PN Segre embedding(so that N = nm + n + m) -I ⊆ S = K [PN] = K [zij :i = 0, . . . , n; j = 0, . . . , m]the idealdefining Y

WHAT CAN WE SAY ABOUT arah(I )?

The case X = Pn has been already settled by Bruns and Schw¨anzl.

(36)

Motivations

In 2005, on Contemporary Mathematics, Singh and Walther

computed thearithmetical rank of certain Segre products. Precisely, they settled the problem described above when

n = 2, d = 3, m = 1.

They showed that (in characteristic different from 3) arah(I ) = 4

After them Song, student of Singh, proved the same statement whenf = x0d+ x1d+ x2d,n = 2,m = 1((char(K ), d ) = 1).

(37)

Motivations

In 2005, on Contemporary Mathematics, Singh and Walther

computed thearithmetical rank of certain Segre products. Precisely, they settled the problem described above when

n = 2, d = 3, m = 1.

They showed that (in characteristic different from 3) arah(I ) = 4

After them Song, student of Singh, proved the same statement whenf = x0d+ x1d+ x2d,n = 2,m = 1((char(K ), d ) = 1).

(38)

Motivations

In 2005, on Contemporary Mathematics, Singh and Walther computed thearithmetical rank of certain Segre products.

Precisely, they settled the problem described above when

n = 2, d = 3, m = 1.

They showed that (in characteristic different from 3) arah(I ) = 4

After them Song, student of Singh, proved the same statement whenf = x0d+ x1d+ x2d,n = 2,m = 1((char(K ), d ) = 1).

(39)

Motivations

In 2005, on Contemporary Mathematics, Singh and Walther

computed thearithmetical rank of certain Segre products. Precisely, they settled the problem described above when

n = 2, d = 3, m = 1.

They showed that (in characteristic different from 3) arah(I ) = 4

After them Song, student of Singh, proved the same statement whenf = x0d+ x1d+ x2d,n = 2,m = 1((char(K ), d ) = 1).

(40)

Motivations

In 2005, on Contemporary Mathematics, Singh and Walther

computed thearithmetical rank of certain Segre products. Precisely, they settled the problem described above when

n = 2, d = 3, m = 1.

They showed that (in characteristic different from 3) arah(I ) = 4

After them Song, student of Singh, proved the same statement whenf = x0d+ x1d+ x2d,n = 2,m = 1((char(K ), d ) = 1).

(41)

Motivations

In 2005, on Contemporary Mathematics, Singh and Walther

computed thearithmetical rank of certain Segre products. Precisely, they settled the problem described above when

n = 2, d = 3, m = 1.

They showed that (in characteristic different from 3)

arah(I ) = 4

After them Song, student of Singh, proved the same statement whenf = x0d+ x1d+ x2d,n = 2,m = 1((char(K ), d ) = 1).

(42)

Motivations

In 2005, on Contemporary Mathematics, Singh and Walther

computed thearithmetical rank of certain Segre products. Precisely, they settled the problem described above when

n = 2, d = 3, m = 1.

They showed that (in characteristic different from 3) arah(I ) = 4

After them Song, student of Singh, proved the same statement whenf = x0d+ x1d+ x2d,n = 2,m = 1((char(K ), d ) = 1).

(43)

Motivations

In 2005, on Contemporary Mathematics, Singh and Walther

computed thearithmetical rank of certain Segre products. Precisely, they settled the problem described above when

n = 2, d = 3, m = 1.

They showed that (in characteristic different from 3) arah(I ) = 4

After them Song, student of Singh, proved the same statement

whenf = x0d+ x1d+ x2d,n = 2,m = 1((char(K ), d ) = 1).

(44)

Motivations

In 2005, on Contemporary Mathematics, Singh and Walther

computed thearithmetical rank of certain Segre products. Precisely, they settled the problem described above when

n = 2, d = 3, m = 1.

They showed that (in characteristic different from 3) arah(I ) = 4

After them Song, student of Singh, proved the same statement whenf = x0d+ x1d+ x2d,n = 2,m = 1((char(K ), d ) = 1).

(45)

What we can prove

(1)arah(I ) ≥ N − 2 for any n, m, f (V+(f ) = X smooth) (2)arah(I ) ≥ N − 1 if n = 2, d (= deg(f )) ≥ 3 (X smooth) We define two sets of polynomials of R of degree d ,PdnandLnd:

f ∈ Pdn⇔ f = xnd+ g with g ∈ (x0, . . . , xn−2)(up to change of coordinates)

f ∈ Lnd⇔ f = xnd+ g with g ∈ (x0, . . . , xn−3)(up to change of coordinates)

(3)arah(I ) ≤ N − 1 for any n, m = 1, f ∈ Pdn

Pdn contains the general polynomial f of degreed ≤ 2n − 1. Pdn contains any polynomial f = x0d+ . . . + xnd

Pd2hascodimension d − 3in the Hilbert scheme of curves of degree d .

(4)arah(I ) ≤ N − 2 for any n, m = 1, f ∈ Lnd

(5)arah(I ) = N − 2for n = 2 and X smooth conic (any m, char(K ) 6= 2)

(46)

What we can prove

(1)arah(I ) ≥ N − 2 for any n, m, f (V+(f ) = X smooth)

(2)arah(I ) ≥ N − 1 if n = 2, d (= deg(f )) ≥ 3 (X smooth) We define two sets of polynomials of R of degree d ,PdnandLnd:

f ∈ Pdn⇔ f = xnd+ g with g ∈ (x0, . . . , xn−2)(up to change of coordinates)

f ∈ Lnd⇔ f = xnd+ g with g ∈ (x0, . . . , xn−3)(up to change of coordinates)

(3)arah(I ) ≤ N − 1 for any n, m = 1, f ∈ Pdn

Pdn contains the general polynomial f of degreed ≤ 2n − 1. Pdn contains any polynomial f = x0d+ . . . + xnd

Pd2hascodimension d − 3in the Hilbert scheme of curves of degree d .

(4)arah(I ) ≤ N − 2 for any n, m = 1, f ∈ Lnd

(5)arah(I ) = N − 2for n = 2 and X smooth conic (any m, char(K ) 6= 2)

Riferimenti

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