ON MINIMUM ENERGY
PROBLEMS*
G. DA PRATO’, A. J. PRITCHARD$, AND J. ZABCZYK
Abstract. A stochastic system described by a semilinear equationwith a small noise is considered. Undersuitablehypotheses,theratefunctionalsfor the family of distributions associatedtothesolutionand theexit timeand exitplaceof the solutionarecomputed.
Keywords, stochasticsystems, optimization, semilinear equations,exit time AMS(MOS)subjectclassifications. 93B05,93C20,93E20
1. Introduction. The paper is concerned with several deterministic optimization questions which arise in thetheory of small noise distributed systems.
Let us assume that a stochastic system is describedby asemilinear equation
(1.1)
dX(AX
+
F(X))dt
+x/
dW,
X(O)
aH,
e> O,
where
A
and F are, respectively, linear and nonlinear parts of the driftterm and Wis a Wienerprocess with incremental covariance
Q
on a Hilbertspace H.Theoptimizationproblemsconsidered in this paperaremotivatedbytheproblem
of finding the rate functionals for the family of distributions
(X:(.)),
e>0. Theyare also related to theproblem of calculating
(for
a given domain) the exit time andexit place oftheprocesses
X(.),
e>0,(see
[4], [5], [11], [12], [14],
[15]).
Hereandin the sequelthe distribution ofarandom variable
:
is denoted as(:).
If
ET(a,"
isthe rate functional forthe familyof measures(XX’
(T)),
e>
0,then also ofimportanceis the functional
E(a, b)
infT>oE-(a,
b),
a,bH,
which is sometimes called the quasipotential([4],
[5]).
For
an appropriate choice of the initialcondition,
E
is the rate functional for the invariant distributions(,)
of theprocess X
.
Assume
that a is a stable equilibrium point for the deterministic systemAz
+
F(z),
and let @ bea set containedin H whichis open with respecttothe strongtopology and contains the point a. Define
-
inf{t :>0;X(t)O}
then
lim+o
In
e(-)
is called the exit rate.Now let
ya,+(.
be a solution to the following controlled equation"f
ay
+
F(y)
+
Q1/Zch,
y(O)
ain which
4’
stands fora square integrable function from[0,
+[
into H.Under fairlygeneral conditions,
(see
[14]),
we haveEr(a, b)
=inf
14,<s)ll
ds;
ya"(T)=b
andsee[5],
[12],
and[14],
1.2)
limIn
e r infE(a, b).
e$O
Receivedbythe editorsSeptember 8, 1989; acceptedfor publicationFebruary 7, 1990.
tScuolaNormale Superiore, Pisa, Italy.
$Institute ofMathematics,Warwick University, England.
Institute ofMathematics, PolishAcademyof Sciences, Warsaw,Poland. 209
The set of all those points where the infimum in
(1.2)
is attained is the exit set, and this also has an important probabilisticinterpretation(see
[4], [5],
[13]).
The presentpaperisconcerned withtheproblem of findingorestimating
E-
andEoo
and is also concerned with theproblem ofminimizingEoo
overtheboundary ofagivensetD. Wewillrefer to them as the minimumenergy problemand the exitproblem,
respectively. We show that in certain important cases explicit solutions are possible. The paper is divided into three parts. The first part is devoted to the minimum energy problem for linear systems. Here we gather partially known results. Basic formulae and estimates are given in Theorem 2.2. Thenextsectionstartsfromanupper
estimate for the energy
Eoo
which,however,
is only validlocally. The main result ofthe paper is formulated inTheorem 3.7 which gives explicit formulae for
Eoo
fortheso called gradientsystems. The first part of the theorem is anextension ofaresultby
Friedlin
[5]
which also allows for a much largerclass ofdrift terms. The second part is concerned withsystemsof second order intime,which are not discussed in[5].
All the basic steps of the proof are the same as those for the related results in finite dimensional spaces(see
[4]);
they require more sophisticated control theoretic andanalytical developments.The final part presentsacompletesolutionof the exitproblem
when the dynamics are linear.
This paper is a shortened version of the report
[3],
to which we will refer for additional details.2. Minimum energy problemfor linear systems. Considera linearcontrol system
(2.1)
y=Ay+Bu,
y(O)=a6H
on a Hilbert space H. The operator
A
generates a C0-semigroup of linear operatorsS(t),
=>
0andBis abounded linear operator fromaHilbertspace UintoH. Wewillalways assume
u(.
L2[0,
T;
U]
for arbitrary T>0.The mild solution of
(2.1)
is given by(2.2)
y(t)
S(t)a
+
S(t- s)Bu(s)
ds,
>- 0.Letusfix T>0and considerthefollowinglinear operator
Lr
actingfromL[0,
T; U]
into H:
(2.3)
Thus
L.u
S(
T-s)Bu(s)
ds.y(
T)
S(
T)a
+
LT-u.
Recallthat ifLis aboundedlinearoperator between Hilbertspaces H1,H2, thenthe value of its pseudoinverse operator L-1
at a point y Im L
H2
is characterized astheunique vectorx
H
such thatLx
y,(x
z,x)
0 for allzH,
Lz
y.Equivalently x
L-y
is the element withthe smallest norm satisfyingLx
y.It
is clear thatthere existsacontrolu(.
L2[0,
T;
U]
transferring a to b in timeT
ifand onlyifbS(T)a
Im
Lr,
and it is clearthat the control which achieves this and minimizes the functional u-*J
Ilu(s)ll
2ds--called the energy functional--is(2.4)
uLr’(b
S( T)a).
Let
usrecall thatthe system(2.1)
isnull controllable in time T>0 if an arbitrarystate b H canbetransferredto0 in time T.
Moreover,
the setT
ofall stateswhichcan be reached from 0 in time T>0 with controls
u(.)
L2[0,
T;
HI
is called thereachable space in time
T.
IfT
is the whole space then the system is said to beexactlycontrollable in time T. Finallyasemigroup
S(t)
is said tobe stableif,for somepositive constants M and ca we have
]]S(t)]]-<
Me-)’(see
[1],
[2]).
Definethe linear operator
Rt
S(r)BB*S*(r)
dr,
>=
O.We
have the following proposition(see
Ill,
[2]).
PROPOSITION 2.1.
(i)
Thefunction
Rt,
>-0, is the unique solutionof
the equationd
(2.5)
-7:(Rtx,
x)=2(RA*x,x)+]]B*x]]
2,
xD(A*),
t>_0;Ro=L
at"’-(ii)
If
A
generatesa stable semigroup then limt_+oRt--
R existsandis the unique solutionof
the equation(2.6)
2(Ra*x,
x)+
[[B*x[]2--O,
XD(A*).
The following theorem gives general results for the functionals
Er(a, b),
theminimal energy oftransferring a to b in time
T,
andE(a,
b),
a,bH,
T> O. In its formulation we will use the convection that ifan element x is not in the domain of an unbounded operator C we setCx][
+00.THEOREM 2.2.
(i)
For arbitrary T>0 anda,b H:ET(a,
b)
IJR2)-’(S(T)a
b)l
.
(ii)
If
S(t)
is stableand the system(2.1)
is null controllable in timeTo
>
0, thenE(0, b)=
]](U’/2)-’bll
2b H.
Moreover,
there exists C>
0, such that(2.7)
]I(R’/2)-’b]I2<-
ET(O,
b)<=
CJI(R’/2)-’bl]
2,
bH,
T>=
To.
Proof
The proof of(i)
can befound,
for instance, in[1].
To
prove(ii)
let usremarkthat the nullcontrollabilityin time
To
isequivalenttothefact that for aconstantC
>
0 and all xH,
f
o
1/2 x 2,
2B*S*(r)x
dr RTo>=
C,
STo)x
Butf
(k+l)T =0 dkTandfor aconstant C2
>
0,IIB*S*(r)xll
drllB*S*(r)xll
dr <-Cllxl
,
xeH.
Consequently, for some constants M
>
0,to>
0,C3
>
0,Io
I[el/2xl[
-
[[B*S*(F)Xl]
dr+C
Y
[Is*(To)xll
k=lIIB*S*(r)xII
dr+C
-rolS*(ro)xll
o k=o+--
(-e-o)
-’lB*S*(r)xll
drC
1/2Hence
Im el/c
lmRro
Sincethe operator(e
1/- /ro R is closed andthus bounded
it follows that
(2.14)
holds.Now
limr,Rr
R
so(2.13)
musthold as well.We now considertwo specialcases.
Assume
thatA’D(A)c
H
H is a negativedefiniteoperatoron a Hilbert space Hand that C’H His abounded operator. The operators
A
and,
=
A
Cdefine Co-semigroups on H and
=
D(-A)I/x
H. The semigroups define mild solutions of the following Cauchy problems(2.8)
2Ax,
x(O)
H
(.9)
2ax
+
c,
x(0)
eD(-a)
/,
(0)
H.The controlled version of
(2.8)-(2.9)
are(.0)
=ay+u,
y(O)=xg
(. )
2
ay
+
c
+
u,y(0)
O(-a)/),
(0)
v eH.We
havethe following theorem.TOM 2.3.
(i) Assume
that the operatorA
isnegativedefinite, thenthe reachablesee
rfor
chesyscem (2.10)
is,for
allT> O,
exactlyD((-A)
/)
and(0, b)
2(-a)’/bl
,
b H.(ii)
If
in addition the operator C is negativedefinite,
bounded and(-C)
/ commuteswith
(-A)
/ then the system(2.11)
is exactly controllable andProo
For
the details of the proof see[3].
The proof that(2.11)
is exactlycontrollable is similar to the onegiven for the one dimensional wave equation in
[2],
although, ofcourse, amoregeneral spectral decomposition is required.
This result does not generalize to arbitrary semigroups; however for analytic
semigroups the first part of
(i)
canbe generalized.To
do this we must introduce thereal interpolation space
D(1/2, 2).
We recallthatD(1/2, 2)
is the set of all x in Hsuch that there exists a function
y(.)
W’(0, ; H)L(O,
;
D(A))
such thaty(0)
x(see
[7]).
THEOREM 2.4.
Suppose
thatA
generates an analytic semigroup onH,
then the reachable setfor
system(2.10)
does not depend on time and is equal toD(1/2, 2).
Moreover
the energy norm((0,.))/
is equivalent to the normof
D(1/2,2).
Proo
Let
T> 0,u(.
L[0,
T;
H];
thenthe solution of(2.10)
is given by;o
y()=
s(-s)u(s)
s
and we have
(see [8])
thaty(.)
W1’2(0,
oo;
H)f’IL2(0, ;
D(A)).
Hence
y(T)
Da(1/2, 2).
Conversely let x
Da(1/2, 2);
then we want to show that there exists a controlu(.)L2[0,
T; H]
such thaty(T)=x. Now
sincexDa(1/2,2)
there existsz(.)
W/2(0, ;
H)f’l
L2(0,
c;
D(A))
such thatz(0)=
x. Choose a C real functiond)("
such that4(0)
0,4)(T)
1 and set( t)
dp(t)z(
T-t),
u( t)
(
t)
A(
t);
[0,
T]
Thenu(-
)Le[0,
T; H],
(t)
y(t)
and:(T)
y(T)
x as required.We now consider
y( t)
S( t)x
+
S(
s)u(s)
dsand first suppose that x
DA
1/
2,2).
Then there existsz(.
W1,2(0,
oo;
H)(qL2(,
oo; D(A))
such thatz(0)--x.
Let h bearealvalued C function suchthath(0)
1,h(T)
0andsety(,t)
h(t)z(t),
theny(0)
x,y(T)
0andp(.
Ay(.
L2[0,
T;
HI.
Thus it sufficesto chooseu(t)
p(t)
Ay(t).
For x H we first chooseu(t)
0 in[0,
T/2];
thusy(T/2)
DA(1/2,
2).
Now bythe previousargumentwe can find a controlu(.)L2[T/2,
T;
HI
such thaty(T)
=0.3. Minimumenergy problemsfor nonlinearsystems. Results like Theorems2.2,2.4 for linear systems do not have immediate generalizationsto nonlinearones.
However
local results can be obtained via linearization as we shall show in Theorem 3.1. This theorem will alsoplayarole in proving Theorem3.7,which isanextension of Theorem 2.3 and is the most important result of the paper.Denote
byV
thespace ImLr
ImR
2
associated withthe control system(2.1),
equipped withthe norm
11.
I]-:
Ilxll-II(R=)-’xl[-
IIZ’xll.
It follows immediately from the control theoretic interpretation that if
<-s,
V,
cV
andIlxll,-<-Ilxll,
xvt.
Let
us assume that for all T>0 sufficiently small, F:VT-
U and for all r>
0, thereexists
Nr,
T>
0 such that(3.1)
IIF(a)-F(b)llu<--N,Tlla-bllT
providedIlallT<--r,
IlbllT<--r.
Considerthe following equation:
(3.2)
3)
(Ay
+
BF(y))+ Bu,
y(0)
0,whichhas the following mild form:
io
(3.3)
y(t)=
S(t-r)BF(y(r))
dr+S(t-r)Bu(r)
dr.TEOREM 3.1.
If
2Nr,
r/-<
1 andIlbll<-r((-2N,,/-)/2N,-,/-)then
Er(0, b)
_-<(llb[l
+
rNr, wV/-)
2.
Wewill need the following
result,
also ofindependent interest.PROPOSITION 3.2.
A
mild solutiony(.)
of
(2.1)
with initial condition 0 isVT-Continuous
on[0,
T].
Proof
Fix 0 s=<
T,
theny(s)- y(t)
S(s- r)Bu(r)
dr-S(t- r)Bu(r)
drS(s- r)B{u(r)-
u(r-(s-
t))If_,.(r)}
dr.Thus,
from the definition of the norms in and(3.4)
[ly(s)
y(t)ll2lly(s)y(t)[
2fo
r
,
]u(r)-u(r-(s-t))I,_,.,l(r)]
dru(r)- u(r-(x-
t))ll
=
dr+I[u(r)ll
zdr.--t
But
theright-hand side of(3.4)
tends to 0 as s- 0 and so the result follows.Proof
The equation(3.2)
canbe written aswhere
F(y)
denotesthe functionF(y(s))
s[0,
T].
If there exists acontrolu(.
that transfer zeroto b in timeT,
then(3.4)
xLrF(y)+
Lru.
Set
(3.5)
uL?l(b-
LrF(y)).
We
will now show that the following equation(3.6)
y(t)=L,F(y)+L,L?(b-LrF(y))
t[0,
T]
has a
Vr-continuous
solution.Note
that then necessarily(r)
F(y)
+
xF()
xand the transferring control is given by
(4.6).
For z Z
C[0, T; Vr]
define(z)
byO(z)(t)
,v()
+
,?(x-F(z)).
It
followsfrom Theorem 4.1 that:
Z Z.Note
O(0)(t)
,?lx
[0,
and hencesup
L,L’
b T-- USo
II(0)ll/--<
IlbllT-
Letw,
zZ,
then(w)()- (z)()
L,[V(w)
V(z)]
+
,’([F(z)
F(w)])
and hence
(w)-
(z)llz
IIL.(F(w)-
F(z))llz
-IIL.L’(L[F(z)-
F(w)])llz
2
IIF(w(s))
f(z(s))[l
dsIf w
IIz
r, zllz
r, thenII(w)- (z)llz
<--2Nr,
TIIw(s)-z(s)ll
ds)
<_-2N,4TII
w-11.
To showthat the iterates
z
(0),
n 1,2,..,
areconvergentit isenoughtoprovethat
IIz
I1
r, for n 1,2,.... Set k2Nr,
r,
then6(o)
IIz
6(o)-
6-1(0)
Ilz
+
6-’(0)
6-=(o)
IIz
+...
+
6=(o)-
6
(0)
IIz
(k-
+
+ k)l[6(0)ll
1-kIlbll
.
So by the induction argumentif
2N,
(1
2N, )
xb r,then
116(o)llz
r for all n 1,2,.... The sequence{z,}
is thus convergent in Z to a solutiony(.
ofthe equation(3.6).
NowIlu(s)[I
=
dsIlb-
gF(u)ll
<=
Ilbllr+
IlF(y(s))ll
g
dsIlbllT
+ Nr,
rIlY(s)II
ds NIlbllT
+
rNr,
T.
This complete the proof.
Remark 3.3. With asimilarprooftothe one above wecan showthatthereexists
aunique solution ofequation
(3.2)
onthe interval[0,
T]
for anycontrol satisfying1-2Nr,
2Nr,
T<
1 and supIIL,ulIT
<,,r
2N,
r
Also, nonzero initial states can be taken into account.
COROLLARY3.4.
Assume
thatfor
agiven T>0 thetransformation
Fsatisfies
(3.1)
with
Nr,
TO
asrO.
en
for
arbitrarye>0 thereexists>0such thatg
IlbllT
<
,
thenEr(O, b)
e.Proo
The result follows immediately from Theorem 3.1.Wewill show that Theorem 2.3 can be extended to nonlinear systems of the form
(3.7)
Ay
U’(y)
+
u,y(O)
ao
H
(3.8)
Ay
U’(y)
+
u,y(O)
ao
D(-A)’/:,
(0)
bo
H.Wewill make the following assumptions
(i) A
is a negativedefinite
operatoron the Hilbertspace H.(ii) U is a
functional from
V=D((-A)
1/2)
intoR+
of
class C1,
U(0)=0,
OU(O)
=0.(iii)
ere
exists a mappingU"
VH,
Lipschitz on bounded setssuch thatDU(x; h)
(U’(x), h),
for all x, hwhereD
U(x; h)
denotes thevalueof
the Frdchet derivativesatxinthe directionh.
(iv)
is apositiveconstant.Example 3.5.
Let
A=(d/dxa),
D(A)=
W(0,
L)
Wa(0,
L).
For any positiveinteger
k,
we shall denote bywk(o,
L)
the Sobolev space consisting of all the realfunctions on
[0,
T]
whichhavesquare integrablederivativesof any orderless orequalto k.
Moreover,
we setW(0,
L)={u
WI(0,
L);
u(0)-u(L)=0}.
ThenV=
D(-A)
1/2=W(O,
L).
DefineU(x)
ck(x(s)) ds,
xV,
where
4
is arealvalued function of class C1.
Itis easyto see thatU’(x)(s)
6’(x(s)),
s[0, L],
x V.The assumptions
(ii)
and(iii)
are satisfied in this case.Example
3.6. The functionalU(x)=
II(-a)’/Zxll2,
xw
obviously satisfies thecondition
(ii)
andDU(x; h)=
2((-A)
1/2x,
(-A)
1/2h),
x,
hV. But
U’(x)
is definedonly forx
D(A),
so(iii)
does nothold.The minimal energy required to transfer
ao
to al for the system(3.7)
and from[]
to[[]
for the system(3.8)
will be denoted byET(ao, al)
andET([o],
[b,]),
respectively. AlsoE(.,.
infT>oET(’,").
We denote by
za(
),
Z[]("
the solutions of the uncontrolled systems(3.9)
Az- U’(z),
z(O)
a H(3.10)
Az
U’(z)
fl,,
z(O)
aD(-A)1/2,
,(0)
b H.THEOREM 3.7.
Assume
that the assumptions(i)-(iv)
hold.(1)
If
a f:D(-a)
1/2 thenE(0,
a)=+.
(2)
If
aD(-A)
1/2 and(-a)l/2z(t)->O
as to in
H,
then(3.11)
E(0,
a)=
]](-a)l/Zall+ZU(a).
(3)
If []
Yfandzg(t)
0 as-
inYf,
then(3.12)
E
O’
-13[ll(-A)’/-all2+2g(a)+llbll]"
Proof
The proofis based on the following identities. For the system(3.7),
withy(O)D(-A)
1/2(3.13)
[lu(s)ll
2ds=-
Ilu(s)+2Ay(s)-2U’(y(s))[[
2ds
+
(-A)’/=y( T)[[
+
2U(y(T))
-II(-m)/=y(0)
22
U(y(0))].
For
the system(3.8),
withy(0)
D(-A)1/2,
p(O)
H,
l
for
llo
(3.14)
Ilu(s)ll
ds=-
[lu(s)-2(s)l[
as
//3
(-A)1/2y(T)
Ila
/2U(y(T))
+ ll.9(
T)ll
=
-II(-A)l/2y(0)112-2U(y(o))-
I1(0)
To
show that(3.13)
holds letus usethe fact that the mild solution of(3.7)
is in factastrong solution. Elementary calculations give
lfo
r(3.15)
\/(1, 2)\i(o,
T,Ilu(s)ll
2ds)=-
Ilu(s)+Zay(s)-ZU’(y(s))ll
2ds)
-2
((s),
Ay(s)- U’(y(s)))
as
o
(3.16)
and
It remains to show that
r
(.f(s),
U’(y(s)))
dsU(y(
T))-
U(y(O))
(3.17)
-2()(s),
Ay(s))
dsI(-A)’/y(
Y)ll
=-
(-A)’/y(0)
-0
In fact the identities
(3.16)
and(3.17)
are true for arbitrary functionsy(.)
fromW1"2(0,
T; H)1"]
L2(0,
T;
D(A)).
To see this considerasequence{yn("
)}
of functions fromC1(0,
T; D(A))
converging to y both inW’2(0,
T;
H)
and inL2(0,
T;
D(A))
topologies. Such asequence exists since the domain
D(A)
is dense in H. For each nand all
[0,
T]
dU(y,(
t))
DU(y,(
t);
))n(t))
(U’(y,(t)), y,(
t))
dtand
d d
II(-A)/y,(t)ll=(Ay(t),
y,(t))= 2(Aye(t),
.9(t)).
dt
So the identities
(3.16)
and(3.17)
hold for each yn, n 1,2,....However,
we can pass to the limit in theaboveidentities andtherefore(3.16)
and(3.17)
hold forgeneral Toprove(3.14)
notethatthe functional U is defined onall state space and is of class C1.
Thus if the controlu(.
is smooth and initial condition is in the domain of the generator thenIlu(s)ll
ds--
Ilu(s)-2.(s)+2.(s)ll
2as
1lot
---
Ilu(s)-2(s)ll
2ds+2
(f(s)-Ay(s)+ U’(y(s)),
)
dsandconsequently
(3.14)
holds in this case. Thegeneralcase is obtainedby astandardapproximation argument.
Notethat if
(t)=Az(t)-U’(z(t)),t[O, T],
then fory(
t)
z( T-
t)
we havej(
t)
+
Ay(
t)
U’(y(
t))
O,
y(O)
z(T), y(T)
z(O),
(0, T).
Moreover,
the functiony(.
is a solutionof(3.7)
whenu(
t)
-2Ay(
t)
+
2U’(y(t)),
e
[0, T],
and for this control the first term on the right-handside of(3.13)
vanishes.Hence
u(.
)e
L2[0,
T;
HI
andEw(O,
a)>=
II(-A)’/2oII2+2U(o)
(3.18)
Ew(z"(T),
a)--II(-m)’/2all2+2U(a)-ll(-A)l/2z"(Y)ll2-2U(z"(y)).
But
Er+,(O,
a)
<=
E,(O,
za( T))
+
Er(za(
T),
a).
Since
(-a)
’/2z"
T)
->0 as T-+ooit follows fromTheorem 3.1 butE(0,
z"(T))
-+0as T->oo. Thus
lim
ET(Z"(T), a)=
I](-A)’/2al[2+2U(a)
rc
and
inf
ET(O,
a)<=
II(-A)/all:+2U(a)
T>0
and so formula
(3.11)
holds. Formula(3.12)
canbe provedin asimilar way.Remark 3.8.
Assume
thatQ
is alinear positive definite operator that commutes withA (more
precisely withthe spectralmeasure associated withA)
and consider thefollowing system:
1
1U
f’
Q-lAy
5Q-(y)
-1/2Q.9 +
uy(O)
xD(-A)1/2,
y(0)
VH.
Thenthe formula
(3.12)
can be generalizedto the following(3.19)
E0
II(-A)l/all+
U(a)+(Ob,
with basically the same proof.
Remark 3.9. Let be a separable Banach space containing H such that the inclusion operator i: Y(- is radonifying. Thismeansthat if is aHilbertspace then
is Hilbert-Schmidt. Then there exists an invariantmeasure on forthe process
lur
_1dX Ydt dY--
Q-AX
+Q-
(x)
QY)
dt+
dWandup to a multiplicative constantis ofthe form
e-(/)(,)p[dx
I
where/x
is a Gaussian invariant measure forthe linear system dX= YdtdY=(Q-AX
QY)
dt+dW.The measure is cylindrical on with meanvector o and covariance operator
(3.20)
R=[
Q-1
01
0
Q-’
The representation
(3.20)
is valid provided we introduce a newbut equivalent innerproduct
(.,.)
on Y((Jail
[a]}
=((_Q_,A)I/Za, (_Q_,A)I/2)+(b,
b2).
bl
b2
The proof ofthis result follows from
[15].
4. Theexitproblem. Fordetails of the stochastic exitproblem see
[5], [12].
Herewe discuss its deterministic analogue. Tofix ideas we concentrate onthe system
(3.7)
and assume that the conditions of Theorem 3.7 are satisfied. In addition let be a Banach space containingD(-A)
/and such that the inclusion operator i: 3- is
randonifying, which means that the image
i(7)
of the cylindrical Gaussian measureN(0, I)
has an extension to a r-additive measure on Borel subsets of.
Example 4.1
(Compare
[5]).
Letd2
D(A)
W(O,
L)(-]
We(O,
L).
Then
D(-A)’/e
W(0,
L).
If E
C[0,
L],
then the inclusion i"Wo(0,
L)-*
$ is radonifying(see
[6]).
Let
@ be abounded open set in $ containing 0. For arbitrary e>
0 define(0@)
{x
eg,
distances
(x, 0@) <
e}
(4.1)
and let r[inf(E(O, b);
b(0@)
fq@},
+r
inf{E(0,
b);
be(0@)
fq@c},
where @ and @c
denote,
respectively, the closure and the complement of @.=
inf{E(0, b);
be0@}.
If
r-=
limr,
r+=
limr+
e$0
then r-_-<
,
r+-
< and we expect that in factr-=
r+=
.
The numbersr-,
r+,
andwillbe
called,
respectively,thelower,
the upper exitrates, andthe exit rate.The following problems are of interest for both deterministic and stochastic
systems.
PROBLEM 4.2. Under what conditions
r-=
r+=
?
PROBLEM 4.3.
Assume
thatr-=
r+=
.
Calculate and describe as explicitly aspossible the set
(4.2)
={b e0@);
E(0,
b)=
}
which will be called the exitset.
For
linear systems some answers to the above questions are available assumingthat g--H(see
[12]);
here we consider a different situation and give rather specificanswersto both theproblems. Namelywe consider the problem
inf
[[Au
2
u
where
A
is a closed operator onH=
L2(F)
with the domainD(A)c
C()=
E,
C()
being thespaceof continuous functions on
F
cR and @ is abounded neighborhoodof0 in
E.
IfuD(A),
we setIlau
II--
/. Wewill assume also that"(i)
TheoperatorG
A
-1isanintegral operatorwithacontinuous kernel
g(.,
)"
Gv(x)
f.
g(x,
y)v(y)
dy,xF,
vH.(ii)
The set @ is of the following form:@
{u
E;
-b(x) <
u(x)
< a(x),
xF}
where
a(.
andb(.
are positive functions onF.
The followingresult holds.
THEOREM 4.4.
Assume (i)
and(ii)
hold. Thenr-=
r+=
and(4.3)
=
inf(a(x)
^
b(x)
g2(x,
y)
dyLet
Fo
be thesetof
all xF
for
which theinfimum
in(4.3)
isattained.If
Fo
isnonempty then=
(vx)(.)" v(.)=
a(x)
^
b(x)
g(x,.),
xFo
Proof
Let us fix xeF
and a positive number c; first we will solve the problem"inf{I
Aull;
(x)_->
c,E}
(if uD(A),
IIAII
+o),
which is equivalent to(4.4)
infIlvl[
2-- inf11 11
Gv(x)c Gv(x)=c
where
Gv(x)=
(g(x,.). v)H.
The proofofthe following lemma is straightforward.LEMMA
4.5. LetH
be a Hilbert space, vH
andc>
0, thenfor
the probleminf{llull,
(u,
v)=
c}
theinfimum
is attainedat uc llvll
andis equal tocll
Thereforethe problem
(4.4)
hasauniquesolutionvX(
cg(x,
)(Iv
g2(x,
Y)
dY)
-1and the minimum value is
c211vx(
)11-2.
The statement of thetheoremnow followseasily.:Example 4.6. Let
Al=(d2/dx2),D(A1)
W(O,
1)71
W2(0,
1),
g=Co(0, 1)
thespace of continuous functions vanishing at0and 1,
U’=
0 and@
{z
g;; Iz(x)l
<
a,x[0,1]}.
PROPOSITION 4.7. Fortheaboveexample
r-=
r+=
4a2 andtheexitsetconsistsof
exactly twofunctions
+/-(a/2)t
if[0,1/2]
S(t)=
(a/2)(1-t)
ift[1/2,1].
Proof
The prooffollows from Theorem4.4 andelementary calculations.:Example 4.8. Here we take
A2
=-A
whereA
is the same as in Example 4.6.Note that then
D(-A2)/=
D(A)
andII(-A)’/zll=
Ldx
(X)
dx.The set is thesame as thatin Example 4.6.
Poosio4.9. Fortheaboveexample
r-=
r+=
48a and theexitset consistsof
exactly twofunctions
+/-?
at(3
4t2)
if[0,
1/2]
(t)
a(1-t)(3-4(1-t)
2)
ift[1/2,1].
Remark 4.10. Itisclearthatasimilarresult istruefor theoperator
An
(-1)
1"We
could also startfrom theoperatorA
(dZ/dx2)
onL2(0,
1;R
e ofsquare integrablevector functions, g
C(0,
1;Re)
and the set @ could be of more general character @{z;
z(s)
T(s),
s[0,
1]}
where Tis amultifunction with values in
R
e.
Someadditional subtleties arise here. Remark 4.11. It would be interesting to consider in detail the caseA
A onL2(F),
F
boundedin Rn,
D(A1)
W(F) W2(F)
andA,
(-1)m+A
Under well-knownconditions,D(Am)c c(F)
and the exit problem, as formulated in Problems 1 and 2 can be posed correctly. Somerelated comments can be found in[5].
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