LABORATORIO --- 1ª Lezione --- 1.1 EXERCISE 5-13
* R. E. Thomas, A. J. Rosa, "The Analysis and Design of Linear Circuits",
* 1st Ed., Prentice Hall, Inc., Englewood Cliffs, NJ, 1994.
* Exercise 5-13, Fig. 5-36, pag. 249.
VS 1 0 DC 10 R1 1 2 1K R2 2 0 2K R3 2 3 3K R4 3 4 4K VA 4 0 DC 0 .DC VS 10 10 1
.PRINT DC V(2) V(3) I(VS) I(VA) .END
PROBLEM 5-13
* R. E. Thomas, A. J. Rosa, "The Analysis and Design of Linear Circuits",
* 1st Ed., Prentice Hall, Inc., Englewood Cliffs, NJ, 1994.
* Problem 5-13, Fig. P5-6, pag. 267.
IS1 0 1 DC 100M IS2 4 0 DC 100M R1 1 4 1K
R2 2 1 1K R3 2 3 1K R4 3 4 1K R5 2 0 2K R6 3 0 2K
.DC IS1 100M 100M 1
.PRINT DC V(2,3) I(R1) V(1) V(0,4)
* La tensione Vx è data da: Vx = V(2,3)
* La corrente Ix è data da: Ix = I(R1)
* La potenza totale è data da: P_total = V(1)*IS1 + V(0,4)*IS2 .END
PROBLEM 5-15
* R. E. Thomas, A. J. Rosa, "The Analysis and Design of Linear Circuits",
* 1st Ed., Prentice Hall, Inc., Englewood Cliffs, NJ, 1994.
* Problem 5-15, Fig. P5-8, pag. 267.
V1 1 0 DC 10 V2 2 1 DC 10 V3 4 0 DC 10 R1 1 3 10K R2 3 0 20K R3 3 2 30K R4 2 4 40K .DC V1 10 10 1
.PRINT DC V(3) I(R3) I(V1) I(V2) I(V3)
* Vx = V(3) --- Ix = I(R3)
* P_total = - V1*I(V1) - V2*I(V2) - V3*I(V3) .END
PROBLEM 5-7
* R .E. Thomas, A. J. Rosa, "The Analysis and Design of Linear Circuits",
* 1st Ed., Prentice Hall, Inc., Englewood Cliffs, NJ, 1994.
* Problem 5-7, Fig. P5-7, pag. 266.
VS 0 3 DC -10 R1 3 1 10K R2 3 2 20K R3 1 0 30K R4 2 0 40K RX 1 2 3K
.DC VS -10 -10 1
.PRINT DC V(1,2) I(VS) V(3,2)
* La tensione Vx è data da: Vx = V(1,2)
* La corrente Ix è data da: Ix = I(Vs)
* La potenza assorbita da R2 vale: P_R2 = [V(3,2)]2/R2 .END
PROBLEM 5-9
*R. E. Thomas, A. J. Rosa, "The Analysis and Design of Linear Circuits",
* 1st Ed., Prentice Hall, Inc., Englewood Cliffs, NJ, 1994.
* Problem 5-9, Fig. P5-9, pag. 266.
VS 4 0 DC 100 IS 1 2 DC 275M R1 4 1 1K
R2 2 1 2K R3 2 3 1K R4 1 0 3K R5 3 0 1K RX 1 3 3K
.DC IS 275M 275M 1
.PRINT DC V(1) I(RX) V(2,1)
* La tensione Vx è data da: Vx = V(1)
* La corrente Ix è data da: Ix = I(RX)
* La potenza del generatore è data da: P_IS = V(2,1)*IS .END
LABORATORIO --- 2ª Lezione --- 2.1
Generatori Dipendenti o Pilotati
EXAMPLE 3.6
* C. R. Paul, "Analysis of Linear Circuits", McGraw-Hill, Inc.,
* New York, 1989.
* Example 3.6, Fig. 3.14a & 3.14b, p. 109.
I1 0 4 DC 2E-3 VS 1 0 DC 10M F1 0 3 V2 2 V2 1 2 DC 0 E1 3 4 4 5 3 V3 5 0 DC 0 R1 2 3 1K R2 4 5 500
.DC VS 10M 10M 1M
.PRINT DC I(V3) V(2,3)
* La tensione V è data da: V = V(2,3)
* La corrente I è data da: I = I(V3) .END
EXAMPLE 3.7
* C. R. Paul, "Analysis of Linear Circuits", McGraw-Hill, Inc.,
* New York, 1989.
* Example 3.7, Fig. 3.15a & 3.15b, pp. 109-111.
VS 1 0 DC 1 I1 4 1 DC 2 V3 3 4 DC 0 F1 0 4 V2 6 V2 5 0 DC 0 R1 1 2 1 R2 2 5 3 R3 2 3 2
.DC VS 1 1 1 .PRINT DC I(V3)
* La corrente Ix è data da: Ix = I(V3) .END
* C. R. Paul, "Analysis of Linear Circuits", McGraw-Hill, Inc.,
* New York, 1989.
* Example 3.8, Fig. 3.16a & 3.16b, pp. 111-112.
* Computation of voltage V, as Vin is varied from -10 V to +30 V.
VS 1 0 DC 1 G1 2 0 1 4 1M H1 0 4 V2 700 V2 3 4 0DC R1 1 2 500 R2 2 3 500 R3 1 4 1K
.DC V1 -10 30 1
* To save output data in .OUT file .PRINT DC V(1,4)
* V = V(1,4)
* Generate .DAT file for the waveform analyzer .PROBE
.END
EXAMPLE 3.9
* C. R. Paul, "Analysis of Linear Circuits", McGraw-Hill, Inc.,
* New York, 1989.
* Example 3.9, Fig. 3.17b, pp. 112-113.
* Plot of output voltage Vo for an op amp, as Vin is varied
* from 1 mV to 500 mV.
V1 2 0 DC 1 V2 1 0 DC 100M E1 5 0 3 4 100K R1 2 4 500 R2 1 3 5K R3 3 0 10K R4 4 3 100K R5 4 6 1K R6 5 6 1K R7 6 0 1K
.DC V1 1M 500M 1M .PRINT DC V(6)
* La tensione Vo è determinata come Vo = V(6) .PROBE
.END
LABORATORIO --- 2ª Lezione --- 2.3
Generatori Dipendenti o Pilotati
EXAMPLE 3.10
* C. R. Paul, "Analysis of Linear Circuits", McGraw-Hill, Inc.,
* New York, 1989.
* Example 3.10, Fig. 3.18b, pp. 114-115.
* Computation of the input resistance of a bipolar transistor amplifier.
I1 0 1 DC 1 E1 3 5 4 5 1E-4 F1 4 5 V1 100 V1 1 2 DC 0 R1 1 0 150K R2 2 3 250 R3 4 5 10K R4 4 0 5K R5 5 0 500 .DC I1 1 1 1 .PRINT DC V(1)
* La resistenza equivalente è determinata dalla relazione: Req = V(1)/I1 = V(1) .END
EXAMPLE 4.2
* C. R. Paul, "Analysis of Linear Circuits", McGraw-Hill, Inc.,
* New York, 1989.
* Example 4.2, Fig. 4.7a & 4.8, pp. 131-133.
VS 1 0 DC 10 I1 1 3 DC 2 I2 2 0 DC 8 H1 3 2 V2 4 V2 4 0 DC 0 R1 3 4 3 R2 2 1 2
.DC VS 10 10 1
.PRINT DC V(2,1) I(V2)
* La tensione è determinata tramite la considerazione: V = V(2,1)
* La corrente è valutata tramite la relazione seguente : I = I(V2) .END
EXERCISE 5-14
* R. E. Thomas, A. J. Rosa, "The Analysis and Design of Linear Circuits",
* 1st Ed., Prentice Hall, Inc., Englewood Cliffs, NJ, 1994.
* Exercise 5-14, Fig. 5-39, p. 252.
VS 1 0 DC 1 FX 3 0 VX 50 VX 5 0 DC 0 VA 4 0 DC 0 R1 1 2 8K R2 2 5 1K R3 2 3 40K R4 3 4 4K
* If .DC and .PRINT commands are not specified, all node-to-datum voltages,
* and currents through voltages sources are reported in the .OUT file .END
EXAMPLE 5-16
* R. E. Thomas, A. J. Rosa, "The Analysis and Design of Linear Circuits",
* 1st Ed., Prentice Hall, Inc., Englewood Cliffs, NJ, 1994.
* Example 5-16, Fig. 5-41, pp. 257-258.
* Evaluation of the input-output relationship of the circuit.
VS1 1 0 DC 0 VS2 2 0 DC 0 G1 3 5 1 5 3M G2 4 5 2 5 3M R1 1 0 500K R2 2 0 500K R3 3 0 8K R4 4 0 8K RDS1 5 3 40K RDS2 5 4 40K .DC VS1 1 1 1 .PRINT DC V(4)
* K1 = V(4) if VS1 = 1, VS2 = 0
* K2 = V(4) if VS1 = 0, VS2 = 1
* .DC command is used to switch on the selected source.
.END
LABORATORIO --- 2ª Lezione --- 2.5
Generatori Dipendenti o Pilotati
SIMULAZIONE .TF
SORGENTE VS IN TENSIONE – USCITA IN TENSIONE PROVA ISTRUZIONE TF
VS 1 0 DC 10V VB 5 4 DC 0V F1 3 4 VB 100 RS 1 2 1K RP 2 5 1K RF 2 3 100K RE 4 0 1K RC 3 0 10K .TF V(4) VS .END
*---
*V(4)/VS = 8.937E-01
*INPUT RESISTANCE AT VS = 1.026E+04
*OUTPUT RESISTANCE AT V(4) = 9.821E+01
*---
SORGENTE IS IN CORRENTE – USCITA IN TENSIONE PROVA ISTRUZIONE TF
IS 0 1 DC 10A VB 5 4 DC 0V F1 3 4 VB 100 RS 1 2 1K RP 2 5 1K RF 2 3 100K RE 4 0 1K RC 3 0 10K .TF V(4) IS .END
*---
*v(4)/IS = 9.167E+03
*INPUT RESISTANCE AT IS = 1.026E+04
*OUTPUT RESISTANCE AT V(4) = 9.167E+02
*---
SIMULAZIONE .TF
SORGENTE VS IN TENSIONE – USCITA IN CORRENTE PROVA ISTRUZIONE TF
VS 0 1 DC 10V VB 5 4 DC 0V F1 3 4 VB 100 VC 4 6 DC 0V RS 1 2 1K RP 2 5 1K RF 2 3 100K RE 6 0 1K RC 3 0 10K .TF I(VC) VS .END
*---
* I(VC)/VS = -8.937E-04
* INPUT RESISTANCE AT VS = 1.026E+04
* OUTPUT RESISTANCE AT I(VC) = 1.109E+03 ---