Weak solutions of equations of the type of non-stationary filtration
D. Andreucci1 E. DiBenedetto23
Appeared in Nonlinear Analysis TMA, 19 (1992), pp.29–41.
Copyright Elsevier, Oxford UK.
1Dipartimento di Matematica U. Dini, Universit`a di Firenze, v.le Morgagni 67/a 50134 Firenze, Italy.
2Department of Mathematics, Northwestern University, Evanston, Ill. 60208 USA.
3Partially supported by NSF Grant DMS 8802883.
1. Introduction.
Consider the filtration equation
(1.1) ut = ∆ϕ(u), in D0(G) ,
where G is a domain in RN+1 and ϕ : R+ → R+ is locally absolutely continuous, non decreasing, ϕ(0) = 0, ϕ(1) = 1 and
(1.2) ∃Λ > 2, such that 1 + 1
Λ ≤ sϕ0(s)
ϕ(s) ≤ Λ, a.e. s ≥ 0.
Theorem. Every local non-negative distributional solution u ∈ L1loc(G) such that ϕ(u) ∈ L1loc(G), is locally H¨older continuous in G.
The proof consists in approximating u by locally bounded solutions of (1.1) to which the results of [4], [5] can be applied.
When ϕ(s) = sm, m > 1, the result is due to Dahlberg–Kenig [3]. Far more than extending Dahlberg–Kenig theorem to general non-linearities ϕ(·), we are interested in giving a different proof of their result which we believe is simpler. Our approach avoids the concept of “traces”, does not require energy estimates and dispenses with the boundedness of Pierre potentials [9].
If f ∈ Co∞(RN), we have
(1.3) Z
RN
∆f (y)
|x − y|N−1dy = − lim
σ→0
Z
|x−y|>σ
(N − 1)fyi(y)(xi− yi)
|x − y|N+1 dy≡ −
N
X
i=1
Ri[fyi].
Here Ri[fxi] are the Riesz transforms of fxi . These are operators of strong type 2,2 ; i.e.
there exists a constant A depending only upon N such that
(1.4) kRi[fxi]k2,RN ≤ Akfxik2,RN ; i = 1, 2, . . . , N.
A crucial fact in the proof is to exploit the connection between the integral in (1.3) and the harmonic extension of f in RN × (0, ∞) for which we refer to (Stein [11], pp. 60–66).
This is the observation of Dahlberg–Kenig that makes the result possible.
Here we propose a different version of this fact that uses only elementary calculus, thereby avoiding the abstract harmonic analysis employed in [3].
2. Structure of the proof.
First we write (1.1) in a classical sense as
(2.1) ∂
∂tuε− ∆ϕε(u) = 0 , in Gε,
where, denoting with z ≡ (x, t) points of G,
Gε ≡ {z ∈ G | dist (z, ∂G) > ε} and ε ∈ (0, 1) is so small that Gε 6≡ ∅;
(i)
uε = u ∗ kε ∈ C∞(Gε); ϕε(u) = ϕ(u) ∗ kε∈ C∞(Gε);
(ii)
k(z) = e
|z|2
|z|2 −1 if |z| < 1 and k(z) = 0 otherwise;
(iii)
kε(z) = 1
koεN+1kz ε
∈ Co∞(|z| < ε), ko = Z
RN+1
k(z)dz ; (iv)
z 7→ uε(z) = Z
RN+1
kε(ζ)u(z − ζ)dζ, (v)
z 7→ (ϕ(u) ∗ kε)(z) = Z
RN+1
kε(ζ)ϕ(u)(z − ζ)dζ.
Inside Gε consider cylinders
Qr(zo) ≡ {|x − xo| < r} × (to, to+ r); r >0, zo ≡ (xo, to) ∈ Gε.
Modulo a translation, we may assume zo ≡ (0, 0) and will be working with balls Br ≡ {|x| < r} and cylinders Qr ≡ Br× (0, r). We also let
Kr ≡ Br× (−r, r).
Step 1.
Modulo a dilation we may assume K2 ⊂ Gε and consider the box Q≡ Q1 ⊂ K2 ⊂ Gε; Q≡ B × (0, 1); B ≡ {|x| < 1}
(in the dilation ϕ(·) is modified by a multiplicative constant depending upon r). Let vε
denote the unique weak solution of
∂
∂tvε− ∆ϕ(vε) = 0 , in Q , (2.2)
vε ∈ C(0, 1; L2(B)), ϕ(vε) ∈ L2(0, 1; W1,2(B)), (vε− uε)(x, 0) = 0 , |x| < 1 ,
(ϕ(vε) − ϕε(u))(x, t) = 0 , |x| = 1 , t ∈ (0, 1).
The notion of weak solution is standard and we refer to [3], [4], [5].
Subtract (2.1) from (2.2) and write the difference in the weak form (here D ≡ (∂x∂
1,∂x∂
2, . . . ,∂x∂
N)) Z
Q
− (vε− uε)ψt+ (D(ϕ(vε) − ϕε(u))) · Dψ dz = 0, (2.3)
ψ∈ W1,2(0, 1; L2(B)) ∩ L2(0, 1; Wo1,2(B)); ψ(·, 1) ≡ 0.
In (2.3) take
(2.4) ψ=
Z1
t
(ϕ(vε) − ϕε(u))dτ ≡ Z1
t
W(τ )dτ.
Then since
Z
Q
D(ϕ(vε) − ϕε(u))Dψdz = Z
Q
DW Z1
t
DW(τ )dτdz = −1 2
Z
Q
d dt
Z1
t
DW(τ )dτ
2dz ≥ 0
we deduce (2.5)
Z
Q
(vε− uε)(ϕ(vε) − ϕε(u))dz ≤ 0.
Remark 2.1. Testing functions like (2.4) were first introduced by Oleinik–Kalashnikov–
Chzhou-Yui-Lin [8].
Step 2.
Lemma 2.1. Every nonnegative local distributional solution of (1.1) such that ϕ(u) ∈ L1loc(G) satisfies
(2.6) uϕ(u) ∈ L1loc(G).
Lemma 2.2. There holds
(2.7)
(θΛϕ(s) ≤ ϕ(θs) ≤ θΛ+1Λ ϕ(s) , ∀θ ∈ (0, 1), ∀s ≥ 0 ; θΛ+1Λ ϕ(s) ≤ ϕ(θs) ≤ θΛϕ(s) , ∀θ ≥ 1, ∀s ≥ 0 . Assuming these two facts for the moment, it follows from (2.5) that (2.8)
Z
Q
vεϕ(vε)dz ≤ Z
Q
vεϕε(u)dz + Z
Q
uεϕ(vε)dz.
We write
Z
Q
vεϕε(u)dz = Z
RN+1
nZ
Q
vε(z)ϕ(u(z − ζ))dzo
kε(ζ)dζ,
and for ζ fixed in the (N + 1)-dimensional ball {|ζ| < ε} we let
E(1) ≡ {z ∈ Q|vε(z) ≤ γu(z − ζ)}; E(2) ≡ {z ∈ Q|vε(z) > γu(z − ζ)},
where γ > 1 has to be chosen. Then Z
Q
vεϕε(u)dz ≤ γ Z
RN+1
n Z
E(1)
[uϕ(u)](z − ζ)dzo
kε(ζ)dζ + γ−Λ+1Λ Z
RN+1
n Z
E(2)
vεϕ(vε)dzo
kε(ζ)dζ
≤ γ Z
Q
[uϕ(u)] ∗ kεdz+ γ−Λ+1Λ Z
Q
vεϕ(vε)dz.
By the properties of mollifiers and Lemma 2.2 we conclude Z
Q
vεϕε(u)dz ≤ γkuϕ(u)k1,K2+ γ−Λ+1Λ Z
Q
vεϕ(vε)dz.
The second integral on the right hand side of (2.8) is estimated analogously by Z
Q
uεϕ(vε)dz ≤ γΛkuϕ(u)k1,K2 + γ−1 Z
Q
vεϕ(vε)dz.
Step 3.
Choosing γ = 4, these estimates have two implications. The first is that by the results of [1], for every compact set K ⊂ Q
kvεk∞,K ≤ Cokuϕ(u)kC1,K1 2 + Co,
where Ci, i = 0, 1 are independent of ε, depend only upon N, Λ and Co depends also upon dist{K, ∂pQ}, where ∂pQ is the parabolic boundary of Q.
It is easily seen that the results of [5] continue to hold for ϕ(·) satisfying (1.2). It follows (see [4], [5]) that ∃α = α(N, Λ) ∈ (0, 1) such that
vε∈ Clocα (Q) uniformly in ε,
and a subnet (indexed again with ε) can be selected so that vε→ w ∈ Clocα (Q), uniformly on compact subsets of Q, and weakly in Lp(Q), p = Λ+1Λ (see (2.7)).
The second consequence is about the convergence of the “mixed terms” in (2.5).
Namely
Lemma 2.3. There holds
ε→0lim Z
Q
vεϕε(u)dz = Z
Q
wϕ(u)dz, (2.9)
ε→0lim Z
Q
uεϕ(vε)dz = Z
Q
uϕ(w)dz.
(2.10)
Now we let ε → 0 in (2.5) and obtain, with the aid of Fatou theorem and Lemma 2.3 Z
Q
(w − u)(ϕ(w) − ϕ(u))dz ≤ 0.
Hence u = w ∈ Clocα (Q) and the theorem follows.
The proof of Lemma 2.1 will be given in the next sections. To prove Lemma 2.2 we observe that if θ ∈ (0, 1), by (1.2), ∀s > 0
lnϕ(θs) ϕ(s) = −
Z1
θ
d
dτ ln ϕ(τ s)dτ = − Z1
θ
1 θ
τ sϕ0(τ s) ϕ(τ s)
dτ ≤ Λ + 1 Λ ln θ ,
implying ϕ(θs) ≤ θΛ+1Λ ϕ(s). The proof of the other inequalities is similar.
Proof of Lemma 2.3: If σ ∈ (0, 1) let Qσ ≡ B1−σ × (σ, 1); Dσ ≡ Q − Qσ, so that
|Dσ| ≤ ωN(N + 1)σ, where ωN is the measure of the unit ball in RN. Then
Z
Q
vεϕε(u)dz − Z
Q
wϕ(u)dz ≤
Z
Qσ
vεϕε(u) − wϕ(u) dz+
(2.11)
+ Z
Dσ
wϕ(u)dz + Z
Dσ
vεϕε(u)dz = Iε(1)(σ) + Iε(2)(σ) + Iε(3)(σ).
Fix δ ∈ (0, 1) arbitrarily small. It follows from the estimates of Step 2 and Fatou theorem that wϕ(u) ∈ L1(Q); then ∃σo ∈ (0, 1) such that
(2.12)
Z
Dσ
wϕ(u)dz ≤ δ, ∀0 < σ ≤ σo.
By the properties of convolutions Iε(3)(σ) =
Z
Dσ
Z
|ζ|<ε
kε(ζ)vε(z)ϕ(u(z − ζ))dζ dz=
Z
|ζ|<ε
kε(ζ)Z
Dσ
vε(z)ϕ(u(z − ζ))dz dζ.
For ζ ∈ Bε fixed, introduce two sets
E1(ζ) ≡ {z ∈ Dσ|vε(z) ≤ γu(z − ζ)} , E2(ζ) ≡ {z ∈ Dσ|vε(z) > γu(z − ζ)}, where γ > 1 has to be chosen. Then
Z
Dσ
vε(z)ϕ(u(z − ζ))dz = Z
E1(ζ)
vεϕ(u(z − ζ))dz + Z
E2(ζ)
vε(z)ϕ(u(z − ζ))dz
≤ γ Z
Dσ
[uϕ(u)](z − ζ)dz + γ−Λ+1Λ Z
Dσ
vεϕ(vε)dz.
Therefore
Iε(3)(σ) ≤ γ Z
|ζ|<ε
kε(ζ)Z
Dσ
[uϕ(u)](z − ζ)dz
dζ+ γ−Λ+1Λ Z
Q
vεϕ(vε)dz
≤ γ Z
Dσ
[uϕ(u)]ε(z)dz + γ−Λ+1Λ Ckuϕ(u)k1,K2,
where C = C(N, Λ) depends only upon N and Λ and [uϕ(u)]ε= [uϕ(u)] ∗ kε. Choose first γ so large that
(2.13) γ−Λ+1Λ Ckuϕ(u)k1,K2 ≤ δ , and, such a γ being fixed, write
γ Z
Dσ
[uϕ(u)]ε(z)dz ≤ γ Z
Q
[uϕ(u)]ε− [uϕ(u)]
dz+ γ
Z
Dσ
uϕ(u)dz.
Since uϕ(u) ∈ L1loc(G), ∃σ1 ∈ (0, 1) such that
(2.14) γ
Z
Dσ
uϕ(u)dz ≤ δ, ∀0 < σ ≤ σ1.
By the properties of convolutions ∃ε∈ (0, 1) such that
(2.15) γ
Z
Q
[uϕ(u)]ε− [uϕ(u)]
dz≤ δ, ∀0 < ε ≤ ε.
Set σ∗ = min{σ1, σo}. Then we deduce from (2.11) Z
Q
vεϕε(u) − wϕ(u)
dz≤ 4δ + Z
Qσ∗
vεϕε(u) − wϕ(u)
dz , ∀0 < ε ≤ ε.
Since vε → w uniformly in Qσ∗ and ϕε(u) → ϕ(u) in L1(Q), ∃ε∗ ∈ (0, 1) such that Z
Qσ∗
vεϕε(u) − wϕ(u)
dz ≤ δ , ∀0 < ε ≤ ε∗.
This proves (2.9) in view of the arbitrariness of δ ∈ (0, 1). The proof of (2.10) is analogous.
3. Preliminary estimates.
Let zo ∈ G, n ∈ N and let R > 0 be so small that {|x − xo| < nR} × (to, to+ R) ⊂ Gε. The number n ∈ N will be determined later only in terms of N, Λ. We may assume zo ≡ (0, 0), R = 1 and set
(3.1) K ≡ {|x| < n} × (0, 1); Bs ≡ {|x| < s}; s= 1, 2, . . . , n.
Let η ∈ Co∞(0, 1) be such that
(3.2) η(t) = 1, t ∈ (1
4,3
4); |ηt| < 8; η≥ 0.
By using the cutoff function η, we derive two basic equations. First set for (x, t) ∈ K
(x, t) 7→ w(x, t) =
t
Z
0
ηΛ+1(τ )ϕε(u(x, τ ))dτ, (3.3)
(x, t) 7→ v(x, t) = (Λ + 1) Zt
0
ητ(τ )ηΛ(τ )uε(x, τ )dτ.
(3.4)
Then multiplying (2.1) by ηΛ+1 and integrating over (0, t), t ∈ (0, 1) we obtain
(3.5) ηΛ+1uε− ∆w = v , in K.
Next define
x 7→ w(x) = w(x, 1) =
1
Z
0
ηΛ+1(τ )ϕε(u(x, τ ))dτ, (3.6)
x7→ v(x) = v(x, 1) = (Λ + 1)
1
Z
0
ηt(τ )ηΛ(τ )uε(x, τ )dτ, (3.7)
and obtain from (2.1), upon multiplication by ηΛ+1 and integration over (0, 1)
(3.8) −∆w = v , in Bn.
The local information contained in these two equations suffices to prove Lemma 2.1.
In particular no trace information is needed.
In the estimates to follow we denote with C = C(N, Λ) a generic positive constant that can be determined quantitatively a priori, only in terms of N and Λ and is independent on ε.
Lemma 3.1. Suppose that w ∈ Lq(Bs) and
kwkq,Bs ≤ C 1 + kϕ(u)k1,K,
for some q ∈ [1, ∞], some C = C(N, Λ) and some s = 1, 2, . . . , n. Then v∈ Lqm(Bs) , m= Λ + 1
Λ , and kvkqm,Bs ≤ C 1 + kϕ(u)k1,Km1 .
Proof: Assume first 1 ≤ q < +∞ . We use (1.2), (3.7) and the properties of the mollifiers;
here z = (x, τ ).
Z
Bs
|v|qmdx≤ C Z
Bs
Z1
0
ηΛuε(x, τ )dτ
qm
dx
≤ C Z
Bs
Z1
0
ηΛ+1(τ )h Z
RN+1
kε(z − ζ)u(ζ)dζiΛ+1Λ dτ
q
dx
≤ C Z
Bs
1
Z
0
ηΛ+1(τ ) Z
RN+1
kε(z − ζ) max{1, u(ζ)}Λ+1Λ dζ dτ
q
dx
≤ C 1 +
Z
Bs
Z1
0
ηΛ+1(τ ) Z
RN+1
kε(z − ζ)ϕ(u(ζ))dζ dτ
q
dx
≤ C 1 + kϕ(u)k1,Kq
. The proof for q = ∞ is analogous.
Proposition 3.1. ∃C = C(N, Λ) such that ∀t ∈ (0, 1) kw(·, t)k∞,B4 ≤ C 1 + kϕ(u)k1,K;
(3.9)
kv(·, t)k∞,B4 ≤ C 1 + kϕ(u)k1,Km1
; (3.10)
kDw(·, t)k2,B4 ≤ C 1 + kϕ(u)k1,K.
(3.11)
Proof: It suffices to consider the case N ≥ 3. Multiply (3.8) by y7→ cN|x − y|2−Nξ(y) , x∈ Bn−2; cN = 1
(2 − N )σN−1,
where σN is the area of the unit sphere in RN and ξ ∈ Co∞(Bn) is such that ξ ≡ 1 on Bn−1; |Dξ| ≤ 2; 0 ≤ ξ ≤ 1. Standard calculations give ∀x ∈ Bn−2
w(x) ≤ C Z
n−1<|y|<n
w(y)|x − y|1−Ndy+ C Z
Bn
|v(y)||x − y|2−Ndy.
This implies ∀x ∈ Bn−2
(3.12) w(x) ≤ C 1 + kϕ(u)k1,K + C Z
Bn
|v(y)||x − y|2−Ndy.
Since ϕ(u) ∈ L1loc(G), by (1.2), u ∈ Lmloc(G), m = Λ+1Λ , and kvkm,Bn ≤ C 1 + kϕ(u)k1,Km1
. Assuming 2m < N , by elliptic theory (see for example [6]),
w ∈ Lq1(Bn−2); q1 = mN
N − 2m; kwkq1,Bn−2 ≤ C 1 + kϕ(u)k1,K.
By Lemma 3.1
kvkq1m,Bn−2 ≤ C 1 + kϕ(u)k1,Km1 ,
and we repeat the process with m replaced by m1 = q1mand Bn replaced by Bn−2 as long as 2m1 < N. Proceeding in this fashion we find numbers
mo = m; qi+1 = N mi
N − 2mi; mi+1 = qi+1mo; i= 0, 1, 2, . . . ,
such that if 2mi < N, w ∈ Lqi+1(Bn−2(i+1)) and kvkqi+1m,Bn−2(i+1) ≤ C 1 + kϕ(u)k1,Km1 . If (j − 1) is the largest non-negative integer such that 2mj−1 < N, we will have 2mj ≥ N and again by elliptic theory (see [6]), ∀q ∈ (1, ∞)
kwkq,Bn−2(j+1) ≤ C 1 + kϕ(u)k1,K; kvkqm,Bn−2(j+1) ≤ C 1 + kϕ(u)k1,Km1 . The number j being quantitatively determined, we take n − 2(j + 1) = 6. Then (3.8) holds in B6 with v ∈ Lp(B6), ∀p ∈ (1, ∞) and estimates (3.9)–(3.10) follow from standard elliptic theory, the definitions of w and v and Lemma 3.1.
To prove (3.11), multiply (3.5) by wξ2 and integrate over B6. Here ξ ∈ Co∞(B6), ξ = 1 on B4, |Dξ| ≤ 1 and 0 ≤ ξ ≤ 1. Estimate (3.11) follows by standard calculations, after we drop the non-negative integral resulting from the first term on the left hand side of (3.5).
Letting
Q∗ ≡ {|x| < 1
2} × (1 4,3
4),
our aim is to estimate the L1 norm of uεϕε(u) in Q∗ independent of ε.
4. Estimating kuεϕε(u)k1,Q∗.
From now on we will work with (3.5) over B4× (0, 1). We multiply it by the testing function
ηΛ+1(t)ϕε(u(x, t))ξ3(x) = wtξ3 and integrate over Q ≡ B1× (0, 1). Here and in what follows (4.1) ξ ∈ Co∞(B1); 0 ≤ ξ ≤ 1; ξ ≡ 1 on |x| < 1
2; |Dξ| ≤ 4.
We also denote with z ≡ (x, t) points in Q and let dz = dxdt. Since (this is again the trick of [8]),
− Z
Q
∆wwtξ3dz ≥ 3 Z
Q
wtDwξ2Dξdz,
the indicated operations give (4.2)
Z
Q∗
uεϕε(u)dz ≤ Z
Q
vwtξ3dz− 3 Z
Q
wtDwξ2Dξdz.
By virtue of Proposition 3.1, Z
Q
vwtξ3dz≤ C 1 + kϕ(u)k1,Km1 Z
Q
wtdz ≤ C 1 + kϕ(u)k1,K2
.
Moreover Z
Q
wtDwξ2Dξdz =
Z
Q
(wξ)tD(wξ)Dξdz − Z
Q
wtξw|Dξ|2dz ≤ C
Z
Q
ft|Df |dz + Ckwk∞,Q Z
Q
wtdz,
where we have set
(4.3) (x, t) 7→ f (x, t) ≡ w(x, t)ξ(x) ∈ C∞(0, 1; Co∞(B1)).
It follows again from Proposition 3.1 that
(4.4)
Z
Q
wtDwξ2Dξdz
≤C 1 + kϕ(u)k1,K2
+ C Z
Q
ft|Df |dz.
Therefore Lemma 2.1 will be proved if we can find an upper bound for the last integral independent of ε. Since f (·, t) ∈ Co∞(B1), ∀t ∈ [0, 1], we write
f(x, t) = cN
Z
RN
∆f (y, t)
|x − y|N−2dy; |Df |(x, t) ≤ C Z
RN
|∆f (y, t)|
|x − y|N−1dy.
From (4.3) and (3.5)
(4.5) |∆f | ≤ |∆f − ηΛ+1uεξ| + ηΛ+1uεξ ≤ ∆f + 2|v|ξ + 4|DwDξ| + 2w|∆ξ|.
Putting this in (4.4) and using Proposition 3.1 we find Z
Q∗
uεϕε(u)dz ≤ C 1 + kϕ(u)k1,K2
+ C Z
Q
ft(x, t) Z
RN
|DwDξ|(y, t)
|x − y|N−1 dy (4.6) dxdt
+ C
Z
Q
ft(x, t) Z
RN
∆f (y, t)
|x − y|N−1dy dxdt
.
Lemma 4.1. ∃C = C(N, Λ) such that ∀t ∈ (0, 1), ∀x ∈ B1, ∀ε ∈ (0, 1)
J≡ Z
RN
|Dw(y, t)Dξ(y)|
|x − y|N−1 dy≤ C 1 + kϕ(u)k1,K.
Proof: By the structure of ξ, the domain of integration in J is B1 ≡ {|y| < 1}. We view x7→ w(x, t) as the restriction to B1 of
x 7→ w(x, t)l(x); where l ∈ C0∞(B4); l ≡ 1 on B3; 0 ≤ l ≤ 1; |Dl| ≤ 2.
Then we estimate
J≤ C Z
B2
|D(wl)|(y, t)
|x − y|N−1 dy;
(wl)(y, t) = cN
Z
RN
∆(wl)(λ, t)
|λ − y|N−2dλ; |D(wl)|(y, t) ≤ C Z
RN
|∆(wl)(λ, t)|
|λ − y|N−1 dλ.
By an estimate similar to (4.5)
|∆(wl)| ≤ ∆(wl) + 2|v|l + 4|DwDl| + 2w|∆l| , and ∀y : |y| < 2
|D(wl)|(y, t) ≤ C Z
RN
∆(wl)(λ, t)
|λ − y|N−1dλ+ C 1 + kϕ(u)k1,K + C Z
{3<|λ|<4}
|DwDl|(λ, t)
|λ − y|N−1 dλ.
If |y| < 2, the last integral is majorized by C
Z
B4
|Dw|(λ, t)dλ ≤ CkDw(·, t)k2,B4 ≤ C 1 + kϕ(u)k1,K ,
by (3.11) of Proposition 3.1. Putting these estimates in the expression of J we obtain J≤ C 1 + kϕ(u)k1,K +
Z
{|y|<2}
dy
|x − y|N−1 Z
RN
∆(wl)(λ, t)
|λ − y|N−1dλ.
We deal with the last term by writing Z
{|y|<2}
dy
|x − y|N−1 Z
RN
∆(wl)(λ, t)
|λ − y|N−1dλ= Z
RN
Z
RN
∆(wl)(λ, t)
|x − y|N−1|y − λ|N−1dλdy−
Z
{|y|>2}
dy
|x − y|N−1 Z
RN
∆(wl)(λ, t)
|λ − y|N−1dλ= L1+ L2.
By M. Riesz composition formula (see [7])
|L1| =
Z
RN
∆(wl)(λ, t)
|x − λ|N−2dλ ≤
Ckw(·, t)k∞,B4 ≤ C 1 + kϕ(u)k1,K.
As for L2 notice that if |x| < 1 and N ≥ 3 by (1.3) and (1.4) we have
L2 ≤ Z
{|y|>2}
dy
|x − y|2(N −1)
12
Z
RN
∆(wl)(λ, t)
|λ − · |N−1dλ 2,RN
≤ CkDw(·, t)k2,B4 ≤ C 1 + kϕ(u)k1,K.
by (3.11) of Proposition 3.1. The Lemma is proved.
We return to (4.6) which by virtue of Lemma 4.1 now becomes
(4.7) Z
Q∗
uεϕε(u)dz ≤ C 1 + kϕ(u)k1,K2
+ C
Z1
0
Z
B1
ft(x, t) Z
RN
∆f (y, t)
|x − y|N−1dy dxdt
. Therefore the proof of Lemma 2.1 reduces to bound the last integral uniformly in ε.
5. The harmonic extension of f .
For t ∈ [0, 1] let (x, s) 7→ F (x, s; t) be the unique classical solution of
∆xF + Fss= 0, in RN × (t, ∞), (5.1)
F(x, t; t) = f (x, t), x∈ RN.
Such an F can be represented by the Poisson kernel. Namely if H(x − y; s − t) = 2cN+1 |x − y|2+ (s − t)2−N−12
,
is the fundamental solution of Laplace’s equation in RN+1 with pole (x, t), then F(x, s; t) =
Z
RN
∂
∂sH(x − y; s − t)f (y, t)dy = (5.2)
2 σN+1
Z
RN
(s − t)
[|x − y|2+ (s − t)2]N+12 f(y, t)dy .
Remark 5.1. From the definitions (3.3) of w and (4.3) of f it follows that (x, s) 7→
F(x, s; 0) ≡ 0.
Using (5.1) and the representation (5.2), we gather a few facts about F . We let
∇F ≡ (DF, Fs) Lemma 5.1. For all t ∈ (0, 1), as s → t,
Fs(x, s; t) → Fs(x, t; t) = −2cN+1
Z
RN
∆f (y, t)
|x − y|N−1dy, in L2(RN);
(5.3)
Ft(x, s; t) → Ft(x, t; t) = ft(x, t) + 2cN+1
Z
RN
∆f (y, t)
|x − y|N−1dy, in L2(RN);
(5.4)
∃C = C(N, Λ) such that ∀t ∈ (0, 1)
∞
Z
t
Z
RN
|∇F |2dxds≤ C 1 + kϕ(u)k1,K2
(5.5) .
Proof: In (5.2) take the s-derivative and observe that Hss= −∆yH. An integration by parts then gives
Fs(x, s; t) = −2cN+1
Z
RN
∆f (y, t)
[|x − y|2+ (s − t)2]N−12 dy ,
and (5.3) follows letting s → t by standard estimates, since f (·, t) ∈ Co∞(B1).
Taking the t-derivative in (5.2) and recalling that −Hts = Hss = −∆yH, gives Ft(x, s; t) =
Z
RN
∂
∂sHft(y, t)dy + Z
RN
H∆f (y, t)dy.
The second integral is −Fs(x, s; t) and therefore it converges in L2(RN) to −Fs(x, t; t) as s → t. The first integral is the harmonic extension of ft(·, t) and as s → t it converges in L2(RN) to ft(·, t) (see Stein [11], p. 62).
One checks that |∇F | ≤ C(t) |x| + s−(N +1)
, as |x| + s → ∞ and that |F | ≤ kf (·, t)k∞,B4 by the maximum principle. Multiply (5.1) by F and integrate by parts over {|x| < ρ} × (t + σ, t + ρ); σ ∈ (0, 1), ρ > 1. Letting σ → 0 and ρ → ∞ and using the
“initial” data (5.3) we get
∞
Z
t
Z
RN
|∇F |2dxds = − Z
RN
f(x, t)Fs(x, t; t)dx ≤ kf k2,B4kFs(·, t; t)k2,RN
≤ Ckf k∞,B4
Z
RN
∆f (y, t)
| · −y|N−1dy
2,RN ≤ by (1.3) and (1.4)
≤ Ckw(·, t)k∞,B4kDf (·, t)k2,RN ≤ C
1 + kw(·, t)k2∞,B4+ kDw(·, t)k22,B4 . Estimate (5.5) now follows from Proposition 3.1.
We may now conclude the proof of Lemma 2.1, by estimating the last integral on the right hand side of (4.7). Multiply (5.1) by Ft(x, s; t) and integrate over RN × (t, ∞) by using the “initial” conditions (5.3) and (5.4). This gives
−2cN+1 Z
RN
ft(x, t)Z
RN
∆f (y, t)
|x − y|N−1dy
dx= 4c2N+1 Z
RN
Z
RN
∆f (y, t)
|x − y|N−1dy2
(5.6) dx
− 1 2
Z∞
t
Z
RN
∂
∂t|∇F (x, s; t)|2dxds.
By (1.3)–(1.4) and Proposition 3.1, the first integral on the right hand side of (5.6) is majorized by C 1 + kϕ(u)k1,K2
, ∀t ∈ (0, 1). Integrating now both sides of (5.6) in dt over (0, 1) we get
(5.7)
Z1
0
Z
B1
ft(x, t)Z
RN
∆f (y, t)
|x − y|N−1dy dxdt
≤C 1 + kϕ(u)k1,K2
+ C
Z1
0
Z(t)dt ,
where
(5.8) Z(t) = −
Z∞
t
Z
RN
∂
∂t|∇F (x, s; t)|2dxds.
Write
Z(t) = − ∂
∂t Z∞
t
Z
RN
|∇F (x, s; t)|2dxds− Z
RN
|∇F (x, t; t)|2dx.
Now ∀t ∈ (0, 1) Z
RN
|∇F (x, t; t)|2dx= Z
RN
|Df (x, t)|2dx+ Z
RN
Fs2(x, t; t)dx
≤ C 1 + kϕ(u)k1,K2
+ C Z
RN
Z
RN
∆f (y, t)
|x − y|N−1dy2
dx
≤ C 1 + kϕ(u)k1,K2
.
Finally we integrate Z(·) over (0, 1) as indicated in (5.7). We use here (5.5) and Remark 5.1 to obtain
Z 1 0
Z(t)dt
≤ 1 + kϕ(u)k1,K2
+ Z ∞
1
Z
RN
|∇F (x, s; 1)|2dxds+ Z∞
0
Z
RN
|∇F (x, s; 0)|2dxds
≤ C 1 + kϕ(u)k1,K2
.
Putting this in (5.7) proves Lemma 2.1 and concludes the proof of the theorem.
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