C. R. Acad. Sci. Paris,t. 316,Série I, p. 983-988, 1993 983 Théorie des groupes/Group Theory
An
invariant
for
subfactors in the
von
Neumann algebra
of
a free group
FlorinRÂDULESCU
Abstract— Inthis Noteweareconsideringanewinvariant forsubfactors inthevonNeumann algebra
if
(Ft)ofafreegroup.Thisinvariantis obtainedby Computingthe Connes's%invariantforthe envelopingvon Neumannalgebra in theitérationofthe Jone'sbasicconstruction for the
given inclusion.In thecaseofthe subfactors considered in[22], [24]thisinvariantiseasilycomputed
asarelativex invariant,in theform considered in[14].
One considerstheinclusion
if
(F„)£se=if
(F„)xieZt2, where6 isaninjectivehomomorphismfrom Zt intoOut(if(FJ) (i.e. a Z„-kernel) with minimalperiodk2 [in Aut(if(F„))].Then there
existsa canonicalcopy8 oflk in x(*&)which can be liftedto Aut(sE)[4].The décompositionof
thegeneratorofthedual action ofÈkon
si
x!jZfcas theproductofa centrally trivialautomorphismand an almost inner automorphism,gives an action ofZt2©Zt2 on the algebra sexljZt. The
algebraicinvariants[9]forthis last actiongiveamoresubtleinvariant for9.
Asan applicationwe showthat, contrary to thecaseoffinitegroupactions(or moregênerai
G-kernels)on thehyperfineII,factor(settled in[2], [9], [18]),thereexistsnon outerconjugate, injective
homomorphisms(i.e. two Z2-kernëls)fromZ2 into Out(if(F,.)),with non-trivial obstruction to
liftingto an action on £?(Fk). Moreover the algebraic invariants[3] do not distinguish between thèse two Z2-kernels. Also,thereexists twonon-outerconjugate,outeractionsofZ2on S(Ft)®R
thatareneither almost inner orcentrally trivial.
Un
invariant pour
les sous-facteurs del'algèbre
devonNeumann
associéeà
Un groupelibre
Résumé— Nous introduisonsun nouvelinvariantpourles sous-facteursdel'algèbrede vonNeumann
if
(Ft) d'un groupe libreFk, en calculant l'invariant% de Comtespourl'algèbre enveloppantede laconstructiondebasedeJonesassociéeàl'inclusiondonnée.Dansle casdessous-facteurs considérés .dans [21], [24] cet invariant peut être facilement calculéen utilisant une version relativepour%,
considéréedans[14].
Onconsidèreune inclusionde typei?(F„)£se=£?(F„)xl e^j.-2>où0estunhomomorphismeinjectif de ï.k dansOut(i?(F„)), depériode minimalek1 [dansAut(if(F,,))]. Alors il existe unsous-groupe canoniqueZtsAut(«e/)dansx(s/)[4].Ladécomposition du générateurde l'action duale deZt sur
s4xlZ,., comme le produit d'un automorphisme centralement trivial et d'un automorphisme dans
Int(.s?),donneuneaction deZ^SZ^surs4xlZt. Onobtient ainsiuninvariantplussubtilpour6,en
considérant les invariants algébrique[9]del'actiondeZt2©Zt2.
Comme application nous montrons que, contrairement au cas du facteur hyperfini de type
IIj (analysé dans [2], [3], [9], [18]), il existe deux homomorphismesinjectifs de Z2 dans
Out(if(Fl))=Aut(^7(Ft))/Int(ïf(Ft)),qui ontles mêmes invariants algébrique[3],mais quinesont
pasextérieurementconjuguées.
Versionfrançaise abrégée—Le but de cette Note est d'introduire un nouvel invariant
pour les sous-facteurs des facteurs de type
II
x associés à un groupe libre. L'invariant quenous proposons est obtenu en calculant l'invariant x de Connes[4] pour l'algèbre de von Neumann enveloppante de la construction de base de Jones, pour l'inclusion donnée.
L'invariant% a étéintroduit par A. Connes([4], [5]) pour résoudre un problème très difficile
posé par Sakai[27] concernant l'existence d'un facteur de type II1 non anti-isomorphe à lui-même.
On rappelle que si M est un facteur de type II1, alors l'invariantx(M) est le groupe
(commutatif,voir [4]) %(M)
=
(Ct(M)D
Int (M))/Int(M)gOut(M)
oùAut (M) estle grouped'automorphismes de M, Int(M) est le groupe des automorphismes intérieurs et Ct(M) est défini par
Ct(M)
=
{ae
Aut (M), || <x(xn)—xn\\2—>0, pour toute suite centralisantex„}.Note présentée par Alain CONNES..
L'INVARIANT. — Soit
AgB
une inclusion d'algèbres de von Neumann finies, soitE\
:B—>A une espérance conditionnelle de B dansAparrapport à une trace fidèle, normalesurB (invariante parE) et soit seoe l'algèbre enveloppantede l'inclusion Aç=B i.e. le terme à
l'infinidans l'itération de la constructionde base deJones[7]pour l'inclusiondonnée). Dans ces
conditions,
X00£0ut(j0,
est un invariant pour l'inclusion
A£B.
(Comme dans[4], la force de l'invariant vient du fait que l'on considère%(séoe),non seulement commeun groupe abstrait, mais comme un sous-groupe deOut^^,)).
Dans les exemples de sous-facteurs des algèbres de von Neumann des groupes libres
considérés dans[24], on peut facilement montrer que cet invariant coïncideavec l'invariant relatif x[14], pour une inclusion des facteurs hyperfinis associés à l'inclusion donnée.
THÉORÈME. — Soit N
g
M une inclusion d'algèbres finies, à prédual séparable et telle qu'ilexiste une base orthonormale deM sur N, de type Pimsner et Popa[20], pour une espérance conditionnelle de M sur N. Soit SE(Fk) lefacteur de type
II
l associé à un groupe libre Fk,
k?±2.
Si sé
=
(SE(Ft)*NM est leproduit libre, amalgaméréduitdes algèbres de von Neumann introduit dans[22], alorsXM=X(N,M).
Ici
x(N,
M) est l'invariant relatif de Connes pour l'inclusionNi=M, considéré dans[14].Comme applicationdes résultats précédents, nousallons construire deux homomorphismes injectifs de Z2 dans Out(SE(Fk)), non extérieurement conjugués, tels que tous les invariants algébriques (voir [9], [3], [18]) coïncident.
THÉORÈME. — Pour tout
£eZ,
k^.2, il existe deux automorphismes<x(eAut(SE(Fk)), telsque les images de at dans Out(SE(Fk)) sont non conjugués et d'ordre deux. De plus, tous
les invariants algébriques[3] pour les deux homomorphismes injectifs de Z2 dans Out(SE(Fk))
coïncident.
COROLLARY. — 77 existe des sous-facteurs de SE(Fk), de profondeur finie ([7], [17]), non
conjugués et tels que tous les invariants des deux inclusions provenant des commutants relatifs
dans la construction de base ([7], [18], [21]) sont identiques.
THEINVARIANT. — Given A<iBan inclusion
of
type II1factors,of
finite index, we letBoe be the enveloping algebra
for
the towerof
algebras in the (iterated) Jones's basic construction[l]for
AgB.
ThenX(BJSOut(BJ
isaconjugacyinvariant
for
A£B.
Hère,for atype
II
xfactorM, x (M) dénotesthe Connes'sinvariant forM[4].Thex (M)invariantwasintroducedby Connes [4]in connectionto a breakthrough construction
that
showed the existenceof
atypeII-L factornot
antiisomorphicto itself.Recall
that
%(M)=
(Ct(M)D Int
(M))/Int(M). HèreCt(M)
is the setof
ailauto-morphisms
a
of
Mthat
hâvethe propertythat
[|a(x„)—x„\\2->0,wheneverxn,
neZ
isacentralséquence in M (z.e. a boundedséquence in M with ||[x„,y]\\2-> 0forany
veM).
Int
(M) is the closureof Int
(M) in the pointwise convergence topology on M, whileAninvariant for subfactors in the algebraofa free group 985
We willshow
that
for the subfactorsin free groupalgebras, considered in [24] (or forthose considered in [22]), this invariant may be computed and
it
coincides with the relativeformof
the invariant x [14]for anassociâtedpair
of
hyperfinite factors.Using the full strength
of
the invariant(which cornes as in [4] by consideringx(Boo)as a subgroup inOut(Boe)
=
Aut(B00)/Int(Boe),rather than
as an abstract abelian group(see also [8], [12], [27])) we obtain as an application
that
the classification theory forfinite group actions (and for G-kernels)
on
typeII
x factors such as SE(Fk) (the vonNeumann algebraof
afreegroupFk) isdifférentfrom the correspondingclassificationtheory
on
the hyperfiniteIIX factor([2],[3], [9], [18]).THEOREM. — There exists two injectivehomomorphismsfrom Z2 zzzZoOut(SE(Fk)),
for
any
keZ,
k^.2,
non-Hftable to an action of~L2 on SE(Fk) [i.e. two Z2-kernelson SE(Fk) with non-trivial obstruction]that are not outer conjugate (in Out) andfor
whichail
thealgebraic invariants([2], [9]) coïncide.
Explicitly this means
that
there exists two (non-inner) automorphismsa;,z'=l,
2 on SE(Fk), havingnon
conjugate images(of
order two) in Out(SE(Fk)). Moreover; both automorphisms arenot
liftable to actionsof
Z2 on SE(Fk)(i.eaf
=
Adgi, &i(gi)=—g;,vgi=g?
~g/~, withg?- projectionsof
trace 1/2in SE(Fk) (see[3], [9])).By [19], the actions on SE(Foe), obtained by multiplying the generators by complex
numbers
of
modulus1 are distinguished (modulo outer conjugacy) by the topologyinducedonZfrom
Aut
SE(FJ.
This is easily seennot
to work in thecaseof
finitecyclicgroups.
For
example ail Z2 actions on SE(F2)that
are obtained by multiplying the generators with±1
or by switching the generators, are conjugate via éléments inAutJ5f (F2), whichbelong to theimage
of
the0(2)
action onSE(F2),consideredin [29].COROLLARY.— There exists twonon-conjugate,
finite
depth subfactors in SE(Fk) havingthesame higher relative commutant invariants([17],[7], [21]).
It
isplausiblethat
an invariantof
the type considered in this Note could beused tosettle Kadison's problem in [13] (see also Sakai's
book
[26], Problem4.4.44)
on
the isomorphismclassof
the algebrasassociâtedto
freegroups.Weare indebted to D. Bisch,V. F.R. Jones,S. Popa and D.Voiculescuforusefulcommentson this Note.
For
theproof of
the nextlemmaseetheproof
of
lemma4.3.3
in[26].LEMMA 1. — Let
NçM
fe
a pair
of
séparable,finite von Neumann algebras so thatthere exists an orthonormalPimsner-Popa[20] basis
for
the inclusionN£M,
with respect to somefaithful, normalconditional expectationfrom
M ontoN. Assume that N, M hâve centerswithtrivial intersection.Then the vonNeumann algebrareduced
free
productsé
=
(SE(Ffc)(x)N)*NM {which by[22] is a type M^
factor)
has the property that ||Egf(y)—v||2^14
max\\[gi,y]\\2, with;=i,2
respect to the inducednormal
faithful
conditional expectation E^ fromse
into N. Hère ghi=l,
2 are twoof
thek
generatorsin Fk, while||x||
2=
r(x*x),
xesé
andT is the traceon
se.
In particularail
centralséquencesinse
are asymptotically containedinN.Thislemma together with lemma
1.4
in[22] andlemma 3in[11]gives:THEOREM2. — Let
NçM
be apair
of
séparable,finite
vonNeumann algebras so that, with respect somefaithful
normalconditional expectationfrom M intoN, there exists ah orthonormal Pimsner Popa[20] basisfor
the given inclusion. Assume that N, M hâvecenterswith trivial intersection.LetsE
=
(SE(Ft)®N)*NM.
ThenX((^(F/£)®N)*NM)^x(N,M).
Moreover in this identification, correspondingéléments in %(sé) and
x(N,
M) hâve tliesame obstructionsto liftingfrom thequotient.
Hère%(N, M) is therelative x invariant[14] for theinclusion
NçM,
where N, Mof
-séparable finitevon Neumannalgebras:
X(N, M)
=
(Ct (N, M)H Int(N,
M))/Int(N, M),where Ct(N, M) is the set
of
ail automorphismsof
M, leavingN
invariant and actingasymptotically trivial on centralséquencesforM
that
are containedinN
andInt
(N, M)is the setofail inner automorphisms
of
Mthat
are implemented byunitariesin N. ; \;COROLLARY3. — Let
^
=
(A^B^C; A^C^D)
be a commuting square [21]of
finitedimensional algebras, which is irreducible (i. e. the centers
of
A, B and respectivelyC, Dhâve trivial intersection)andX-Markov ([7], [6])i.e. there existsa X^Markovtrace, in the sensé
of
Jones [7]for
C^A,
which restrictsto aX-Markov tracefor
D£B).
By[24]
(y(Fl)®B)*BA2(^,(Ft))®D)*DC
isafiniteindexinclusionoftypell1factors
[that are isomorphic SE(FN)
for
someN>1].
Let seoe be the envoloping von Neumann algebrafor
the towerof
algebras in the iterated Jones's basic constructionof
the given inclusion.Notethatse
x is isomorphic to (SE(Ft)®Boe)*B Aoe. HèreBM,Aoe areobtained
byiterating thebasic construction
for
the inclusionsDi=B andrespectivelyCgA.
ThenLEMMA 4 ([17], [14], [15], [1], [23]).
-
Let 6 be a Z4 action ona
copy R_xof
thehyperfiniteJl1
factor
so that 9 induces a Z2-kernelon R_x with obstruction —1 [3]. Let R0= R_1XeZ4.
Then%(R_UR0)^Z2®Z2.
Moreover,
for
exactly oneof
the two copiesof
Z2 in %(R_1, R0), there exists no obstructionto liftingfrom the quotient.Wemayassume(see [10])
that
The fc-thstep inthe iteratedbasicconstruction forthisconstructionis:
where (Uk)keZ is a family
of
unitaries with fourpoint
spectrumsothat
each spectral projection for Uk has trace 1/4 andg=g+—
g-'is
a selfadjoint unitary whose spectralprojections g± hâve trace 1/2. We hâve the following relations
Tj£=l,
keZ,
U,£gU*=
-g~ifk=0,
1, UkgUj?=
g,if/ceZ/{0,
1} andUtUt+1Ujf
=
y=ÏUt+1
(thetrace onthis constructionis specifiedbyrequiring
that
eachnon-trivial monomialin the U;t's andg
hâve zéro trace). With this notations, a commuting square for the inclusionR
_ !
£
R0 isgivenbySince
U0eB
nomializesA and AdUo|c=
-A-dg|c,whilegeD,
we get:LEMMA 5. — With A, B, C, D as before, (SE(Ffc)®B)*BAis isomorphic to the cross
product
of
(SE(Fk)®D)*DCby the Z4 action on (SE(Fk)®T>)*DC induced by AdU0. [Note that this action is infact
an injective Z2-kernelon (SE (F/c)(x)D):ilcDCwith obstruction-lAninvariant for subfactorsin the algebraof afree group 987
Moreover, by Corollary3, the enveloping algebra
for
the inclusion before issé
=
(SE(Ft)®R_1)*R_1R0 andhence,by theprecedinglemma, %(sé)^,Z2®Z2isgênera- 'tedby
AdU?^
\^
andbyAdU0U_1
\^.Thereexistsno obstructiontolifting toAut
(sf)
for
thefirst
copyof
Z2, whilefor
thesecondcopyof
Z2, theobstructionis —1.LEMMA 6. — With the notations before, let ÉS
=
sé
MZ2, where the Z2 action onse
is induced by:Ad\3\i\sieri(sé)
(this action is an invariantfor
se). Let s be the dual action on the cross product. Then SE isomorphic to(^?(Ft)®Q_1)*Ql
Q0, whereQ_
= {R_ls
UI-L}", Q0=
{R0, \)2-1}". Moreover we hâve thefollowing décompositionfor
s:where
.5'1=.?AdU0U_1eInt(J'),
52=AdUgU*
1eCt(SS). In addition sf= Adh,
with h=
X5\gesé andsi(li)=—h.
The décompositionabove prevents SE from being isomorphic
to
Jones's example ([8],inanalogy with the construction in[4]). We recall
that
in Jones'sexample one considersN=(i?
(FN)®R0)x|TZ2 fora
suitable actiony. Thenx(N) =
Z2©Z2,where, forexactly oneof
the two copiesof
Z2 inx (N)<iOut(N), there exists no obstruction for lifting toan action on N. By[4] (seealso[8]) this copy (denotedbyy) corresponds to the dual Z2 action for
N=(if
(FN)®R0)X!YZ2.ByTakesaki dualitywe get:PROPOSITION7. — With the notations before, the dual action y on the cross
pro-duct
NxjçZ2,
has décompositionof
theform:
y= txt2AdW,
wherez1eCt(N
XIçZ2),Z2eInt(Nx]çZ2). Moreover there exists selfadjoint unitarieseI==e'+—e'_, with
e\
projec-tions
of
trace 1/2, so that tf=
Ade1,tt(el)=
-^el, tt(e,-)=
ep ii=j.COROLLARY8.
-
With thenotationsabove,Nsrf
=
(5'(Fl.)®R_1)*E_,Ro-Proof.
-
Assume the contrary. ThenSE=
sé
Y-Z2, N=(JSf(FN)(x)R0) !*YZ2 would beisomorphic(sinceineach
of
thetwocasestheZ2 actionis canonical). Moreoverit
wouldfollow
that
the corresponding dualactions hâve thesanie image in Out, and thus by[3],wemay assume
that
they areequal.Since in N=(„S?(FN)®R0)KrZ2, the décomposition
of
an automorphism as thepro-duct
of
a centrally trivial automorphism and an almost inner automorphism,is unique(moduloinner automorphism), itwould follow
that
the décompositions= sïs2
(regardedasah action
of
Z4©Z4)isouter conjugateto thesimilaractiondescribed bytu
t2 in thepreceding lemma. Butthisisimpossible becausethetwoactionshâve différent
characteris-tic invariants (see [9]). [Since t1(e2)
=
e2, •(t^y2=
Adel, while, with the notations inProposition5,
st(h)=
—h, sf=
Aàh.]PROPOSITION9. — Let
N
be thefactor
constructedin [8]. Thenthere exists subalgebrasA<=B z'zz
N
so that Ais isomorphic to (SE(Fk), B is the crossproduct AX)^Z4, whereQ isa Z2-kernelon A with non-trivial obstruction (to lifting). Moreover
N
is the envelopingalgebra
for
the inclusionA<iB and Ais isomorphic to SE(Fk).Noteremisele 10février1993,acceptéele 12mars1993.
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DepartmentofMathematics, UniversityofCaliforniaatBerkeley, Berkeley, Ca 94720,USA and InstituteofMathematicsofthe Romanian Academy.